Crappy script to parse a honcho log and get a sorted list of services that took the longest time before serving a request.

parse_honcho_log.py

#!/usr/bin/env python

import dateutil.parser
import operator
import pprint
import sys

with open(sys.argv[1]) as f:
    log = f.readlines()

last_times = {}
items = {}

for l in log:
    if 'HTTP/1.1' in l:
        continue

    l = l.strip()
    if l.count('|') < 3:
        l += ('|' * (3 - l.count('|')))

    parts, cmd, _, _ = l.split('|')
    time, service = parts.strip().split(' ')

    time = dateutil.parser.parse(time)

    if service not in last_times:
        items[service] = 0.0
    else:
        last = last_times[service]
        if time == last:
            continue
        items[service] += (time - last).seconds

    last_times[service] = time

pprint.pprint(sorted(items.items(), reverse=True, key=operator.itemgetter(1)))