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Created September 19, 2012 17:54
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Solution to the Zebra Puzzle in F# as shown at the Zurich F# Users Meetup group
//http://en.wikipedia.org/wiki/Zebra_Puzzle
// Zebra Puzzle
//
//1 There are five houses.
//
//2 The Englishman lives in the red house.
//
//3 The Spaniard owns the dog.
//
//4 Coffee is drunk in the green house.
//
//5 The Ukrainian drinks tea.
//
//6 The green house is immediately to the right of the ivory house.
//
//7 The Old Gold smoker owns snails.
//
//8 Kools are smoked in the yellow house.
//
//9 Milk is drunk in the middle house.
//
//10 The Norwegian lives in the first house.
//
//11 The man who smokes Chesterfields lives in the house next to the man with the fox.
//
//12 Kools are smoked in a house next to the house where the horse is kept.
//
//13 The Lucky Strike smoker drinks orange juice.
//
//14 The Japanese smokes Parliaments.
//
//15 The Norwegian lives next to the blue house.
//
//Who drinks water? Who owns the zebra?
//
//Each house is painted a different color, and their inhabitants are of different nationalities, own different pets, drink different beverages and smoke different brands of American cigarettes.
namespace ZebraDemo
module programOrdered =
let rec permutations inputlist taken =
seq { if Set.count taken = List.length inputlist then yield [] else
for l in inputlist do
if not (Set.contains l taken) then
for perm in permutations inputlist (Set.add l taken) do
yield l::perm }
let myperms = permutations [1;2;3] Set.empty
Seq.length myperms
Seq.toList myperms
let splitToTuple = function
| [fst; sec; thrd; fth; ffth] -> (fst, sec, thrd, fth, ffth)
| _ -> failwith "wrong list format"
let nextTo (frst, sec) =
frst - 1 = sec || frst + 1 = sec
let myHouses = [1..5]
let myHousePerms = permutations myHouses Set.empty
Seq.length myHousePerms
let myOrderedAnswer =
[for myCountryList in myHousePerms do
let (England, Spain, Ukraine, Japan, Norway) = splitToTuple myCountryList
if Norway = 1 then
for myColorList in myHousePerms do
let (red, green, ivory, yellow, blue) = splitToTuple myColorList
if England = red &&
green - 1 = ivory &&
nextTo (Norway, blue) then
for myDrinkList in myHousePerms do
let (coffee, tea, milk, oj, WATER) = splitToTuple myDrinkList
if Ukraine = tea &&
green = coffee &&
milk = 3 then
for mySmokeList in myHousePerms do
let (oldGold, kools, chesterfields, luckyStrike, parliaments) = splitToTuple mySmokeList
if yellow = kools &&
luckyStrike = oj &&
Japan = parliaments then
for myPetList in myHousePerms do
let (dog, snail, horse, fox, ZEBRA) = splitToTuple myPetList
if Spain = dog &&
oldGold = snail &&
nextTo(chesterfields, fox) &&
nextTo(kools, horse) then
yield [("red", red); ("green", green); ("ivory", ivory); ("yellow", yellow); ("blue", blue);
("England", England); ("Spain", Spain); ("Ukraine", Ukraine); ("Japan", Japan); ("Norway", Norway);
("coffee", coffee); ("tea", tea); ("milk", milk); ("oj", oj); ("WATER", WATER);
("dog", dog); ("snail", snail); ("horse", horse); ("fox", fox); ("ZEBRA", ZEBRA);
("oldGold", oldGold); ("kools", kools); ("chesterfields", chesterfields); ("luckyStrike", luckyStrike); ("parliaments", parliaments)] ]
let ans = List.head myOrderedAnswer
let selectFromList houseNum =
List.filter (fun (fst, snd) -> snd = houseNum) ans
|> List.map (fun (fst, snd) -> fst)
printfn "house 1:"
printfn "%A" (selectFromList 1)
printfn "house 2:"
printfn "%A" (selectFromList 2)
printfn "house 3:"
printfn "%A" (selectFromList 3)
printfn "house 4:"
printfn "%A" (selectFromList 4)
printfn "house 5:"
printfn "%A" (selectFromList 5)
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