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September 19, 2012 17:54
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Solution to the Zebra Puzzle in F# as shown at the Zurich F# Users Meetup group
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//http://en.wikipedia.org/wiki/Zebra_Puzzle | |
// Zebra Puzzle | |
// | |
//1 There are five houses. | |
// | |
//2 The Englishman lives in the red house. | |
// | |
//3 The Spaniard owns the dog. | |
// | |
//4 Coffee is drunk in the green house. | |
// | |
//5 The Ukrainian drinks tea. | |
// | |
//6 The green house is immediately to the right of the ivory house. | |
// | |
//7 The Old Gold smoker owns snails. | |
// | |
//8 Kools are smoked in the yellow house. | |
// | |
//9 Milk is drunk in the middle house. | |
// | |
//10 The Norwegian lives in the first house. | |
// | |
//11 The man who smokes Chesterfields lives in the house next to the man with the fox. | |
// | |
//12 Kools are smoked in a house next to the house where the horse is kept. | |
// | |
//13 The Lucky Strike smoker drinks orange juice. | |
// | |
//14 The Japanese smokes Parliaments. | |
// | |
//15 The Norwegian lives next to the blue house. | |
// | |
//Who drinks water? Who owns the zebra? | |
// | |
//Each house is painted a different color, and their inhabitants are of different nationalities, own different pets, drink different beverages and smoke different brands of American cigarettes. | |
namespace ZebraDemo | |
module programOrdered = | |
let rec permutations inputlist taken = | |
seq { if Set.count taken = List.length inputlist then yield [] else | |
for l in inputlist do | |
if not (Set.contains l taken) then | |
for perm in permutations inputlist (Set.add l taken) do | |
yield l::perm } | |
let myperms = permutations [1;2;3] Set.empty | |
Seq.length myperms | |
Seq.toList myperms | |
let splitToTuple = function | |
| [fst; sec; thrd; fth; ffth] -> (fst, sec, thrd, fth, ffth) | |
| _ -> failwith "wrong list format" | |
let nextTo (frst, sec) = | |
frst - 1 = sec || frst + 1 = sec | |
let myHouses = [1..5] | |
let myHousePerms = permutations myHouses Set.empty | |
Seq.length myHousePerms | |
let myOrderedAnswer = | |
[for myCountryList in myHousePerms do | |
let (England, Spain, Ukraine, Japan, Norway) = splitToTuple myCountryList | |
if Norway = 1 then | |
for myColorList in myHousePerms do | |
let (red, green, ivory, yellow, blue) = splitToTuple myColorList | |
if England = red && | |
green - 1 = ivory && | |
nextTo (Norway, blue) then | |
for myDrinkList in myHousePerms do | |
let (coffee, tea, milk, oj, WATER) = splitToTuple myDrinkList | |
if Ukraine = tea && | |
green = coffee && | |
milk = 3 then | |
for mySmokeList in myHousePerms do | |
let (oldGold, kools, chesterfields, luckyStrike, parliaments) = splitToTuple mySmokeList | |
if yellow = kools && | |
luckyStrike = oj && | |
Japan = parliaments then | |
for myPetList in myHousePerms do | |
let (dog, snail, horse, fox, ZEBRA) = splitToTuple myPetList | |
if Spain = dog && | |
oldGold = snail && | |
nextTo(chesterfields, fox) && | |
nextTo(kools, horse) then | |
yield [("red", red); ("green", green); ("ivory", ivory); ("yellow", yellow); ("blue", blue); | |
("England", England); ("Spain", Spain); ("Ukraine", Ukraine); ("Japan", Japan); ("Norway", Norway); | |
("coffee", coffee); ("tea", tea); ("milk", milk); ("oj", oj); ("WATER", WATER); | |
("dog", dog); ("snail", snail); ("horse", horse); ("fox", fox); ("ZEBRA", ZEBRA); | |
("oldGold", oldGold); ("kools", kools); ("chesterfields", chesterfields); ("luckyStrike", luckyStrike); ("parliaments", parliaments)] ] | |
let ans = List.head myOrderedAnswer | |
let selectFromList houseNum = | |
List.filter (fun (fst, snd) -> snd = houseNum) ans | |
|> List.map (fun (fst, snd) -> fst) | |
printfn "house 1:" | |
printfn "%A" (selectFromList 1) | |
printfn "house 2:" | |
printfn "%A" (selectFromList 2) | |
printfn "house 3:" | |
printfn "%A" (selectFromList 3) | |
printfn "house 4:" | |
printfn "%A" (selectFromList 4) | |
printfn "house 5:" | |
printfn "%A" (selectFromList 5) |
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