Lists all participants in a Google Meet meeting.

boorkmarklet.md

The following bookmarket shows a popup with the name of the participants separated by newlines.

javascript:-function(maxStrLength = 2000) { try { function findParticipants(current, depth = 0) { if (depth > 7) return; if (typeof current !== "object" || current === null || current === window) return; const descriptors = Object.getOwnPropertyDescriptors(current); for (const prop in descriptors) { if (prop.startsWith('["spaces/')) return Object.values(current); const item = findParticipants(descriptors[prop].value, depth + 1); if (item !== undefined) return item; } } const rootState = Object.entries(window).find(x => x[0].startsWith("closure_lm_"))[1], participants = findParticipants(rootState), names = []; function findName(obj) { for (const prop in obj) { const value = obj[prop]; if (typeof value === "object" && value !== null && typeof value[1] === "string") return value[1]; } } for (let i = 0; i < participants.length; i++) { const name = findName(participants[i]); if (names.indexOf(name) === -1) names.push(name); } if (names.length === 0) throw new Error("Could not find any name."); names.sort((a, b) => a.localeCompare(b)); const groups = names.slice(1).reduce((groups, name) => { if (groups[0].length + name.length + 1 >= maxStrLength) { groups.unshift(name); } else { groups[0] += "\n" + name; } return groups; }, [names[0]]).reverse(); for (let i = 0, {length} = groups; i < length; i++) { const suffix = length === 1 ? "" : " (" + (i + 1) + "/" + length + ")", message = "Please find the list of participants below" + suffix + "."; if (prompt(message, groups[i]) === null) break; } } catch (e) { alert("Unexpected error when running the script: " + e); }}()

This code can be generated by evaluating:

`javascript:${await fetch("https://gist.githubusercontent.com/71/7296ec9d44af7d0f1fb36b053bbe2219/raw/google-meet-participants.js").then(x => x.text())}`.replace(/\n|\/\*[\s\S]+?\*\//g, '').replace(/ +/g, ' ')

google-meet-participants.js

-function(maxStrLength = 2000) {
  try {
    /* 1. Find the objects corresponding to the participants by recursively
          walking the state of the webapp. */
    function findParticipants(current, depth = 0) {
      if (depth > 7)
        return;  /* We can find it at a lower depth. */
      if (typeof current !== "object" || current === null || current === window)
        return;  /* We're only interested in objects. */

      /* Iterate over descriptors to make sure we don't access computed properties. */
      const descriptors = Object.getOwnPropertyDescriptors(current);

      for (const prop in descriptors) {
        if (prop.startsWith('["spaces/'))
          /* We're looking for the object whose keys start with '["spaces/'. */
          return Object.values(current);

        const item = findParticipants(descriptors[prop].value, depth + 1);

        if (item !== undefined)
          return item;
      }
    }

    const rootState = Object.entries(window).find(x => x[0].startsWith("closure_lm_"))[1],
          participants = findParticipants(rootState),
          names = [];

    /* 2. For each object, determine the participant's name. */
    function findName(obj) {
      /* The property names are non-deterministic and may change at any time, but the
         participant's name is always at 'participant.Aa[1]', where 'Aa' can be an
         arbitrary string.
         Walk the object and hope that the first match corresponds to the string. */
      for (const prop in obj) {
        const value = obj[prop];

        if (typeof value === "object" && value !== null && typeof value[1] === "string")
          return value[1];
      }
    }

    for (let i = 0; i < participants.length; i++) {
      const name = findName(participants[i]);

      if (names.indexOf(name) === -1)
        /* 3. Remove duplicates. */
        names.push(name);
    }

    if (names.length === 0)
      throw new Error("Could not find any name.");

    /* 4. Sort the names lexicographically. */
    names.sort((a, b) => a.localeCompare(b));

    /* 5. Chrome limits to 2K characters the number of characters in the string given
          to "prompt", so we split the output in several groups if needed. */
    const groups = names.slice(1).reduce((groups, name) => {
      if (groups[0].length + name.length + 1 >= maxStrLength) {
        groups.unshift(name);
      } else {
        groups[0] += "\n" + name;
      }

      return groups;
    }, [names[0]]).reverse();

    /* 6. Finally, output all groups using "prompt". */
    for (let i = 0, {length} = groups; i < length; i++) {
      const suffix = length === 1 ? "" : " (" + (i + 1) + "/" + length + ")",
            message = "Please find the list of participants below" + suffix + ".";

      if (prompt(message, groups[i]) === null)
        break; /* User pressed "Cancel", so we stop the loop. */
    }
  } catch (e) {
    alert("Unexpected error when running the script: " + e);
  }
}()

Hi, I am trying to show participant in a popup window in google extension. I tried your code but it did not work. Can you provide some instruction?