Script to reorder a strings.xml according to another ordered file. Useful if you want your translations to be ordered in the same order.

reorder_strings.xml.go

package main

import (
	"encoding/xml"
	"fmt"
	"io/ioutil"
	"os"
)

type resources struct {
	XMLName   xml.Name   `xml:"resources"`
	Resources []resource `xml:"string"`
}

type resource struct {
	XMLName xml.Name `xml:"string"`
	Name    string   `xml:"name,attr"`
	Value   string   `xml:",innerxml"`
}

func readResourcesFrom(file string) (*resources, error) {
	xmlFile, err := ioutil.ReadFile(file)
	if err != nil {
		return nil, err
	}

	res := new(resources)
	err = xml.Unmarshal(xmlFile, res)
	if err != nil {
		return nil, err
	}

	return res, nil
}

func main() {
	if len(os.Args) != 3 {
		fmt.Fprintf(os.Stderr, "Usage: %s file.xml ordered.xml\n", os.Args[0])
		os.Exit(1)
	}

	file, err := readResourcesFrom(os.Args[1])
	if err != nil {
		fmt.Fprintln(os.Stderr, "Error parsing file:", err)
		return
	}
	ordered, err := readResourcesFrom(os.Args[2])
	if err != nil {
		fmt.Fprintln(os.Stderr, "Error parsing ordered file:", err)
		return
	}

	var result resources
	for _, orderedString := range ordered.Resources {
		found := false
		for i, fileString := range file.Resources {
			if fileString.Name == orderedString.Name {
				result.Resources = append(result.Resources, fileString)
				file.Resources = append(file.Resources[:i], file.Resources[i+1:]...)
				found = true
				break
			}
		}
		if !found {
			fmt.Fprintln(os.Stderr, "No matching element found for ordered element: ", orderedString.Name)
			return
		}
	}
	if len(file.Resources) > 0 {
		fmt.Fprintf(os.Stderr, "%d resources left after processing.\n", len(file.Resources))
		for _, fileString := range file.Resources {
			fmt.Fprintln(os.Stderr, "-", fileString.Name)
		}
	}

	res, err := xml.MarshalIndent(result, "", "    ")
	if err != nil {
		fmt.Fprintln(os.Stderr, "Error marshaling result:", err)
		return
	}
	fmt.Println(string(res))
}