Hackerrank Java Anagrams Solution

Hackerrank Java Anagrams Solution

import java.util.Scanner;
public class Solution {
    static boolean isAnagram(String a, String b) {
       
//      // once you declare a.toUppercase you should assign it to a. you cannot define it as just a.toUppercase... 
//      //I solved it with the long way however I could put a and b in a character array and then use  Arrays.sort(arrayname). after this steps convert them to string and check if they are equel.
        a=a.toUpperCase();
        b=b.toUpperCase();
        boolean ret = false;
        StringBuilder c= new StringBuilder(b);

        if(a.length()==b.length()){
            for(int i=0; i<a.length();i++){
                for(int j=0; j<c.length();j++){
                    if(a.charAt(i)==c.charAt(j)){
                            c.deleteCharAt(j);
                        if(i==a.length()-1 && c.length()==0){
                            ret=true;
                            break;
                        }
                        break;

                    }

                }
            }
        }return ret;
   
   }
        
         public static void main(String[] args) {
    
        Scanner scan = new Scanner(System.in);
        String a = scan.next();
        String b = scan.next();
        scan.close();
        boolean ret = isAnagram(a, b);
        System.out.println( (ret) ? "Anagrams" : "Not Anagrams" );
    }
}

import java.io.;
import java.util.;

public class Solution {
public static String lvalue(String s){
char str[]=new char[s.length()];
str=s.toCharArray();
char temp;
for(int i=0;i<s.length();i++){
for(int j=0;j<s.length()-1;j++){
temp=str[j+1];
if(str[j]>str[j+1]){
str[j+1]=str[j];
str[j]=temp;
}
}
}
String ss = new String(str);
return ss;
}
public static void main(String[] args) {
String str1,str2;
Scanner in = new Scanner(System.in);
str1=in.next();
str2=in.next();
str1=str1.toLowerCase();
str2=str2.toLowerCase();
if(str1.length()==str2.length()){
str1=lvalue(str1);
str2=lvalue(str2);
if(str1.equals(str2))
System.out.println("Anagrams");
else
System.out.println("Not Anagrams");
}
else
System.out.println("Not Anagrams");
}
}

A much more simple solution:

private static boolean isAnagram(String a, String b) {
    if (a.length() != b.length()) {
        return false;
    }
    a = a.toLowerCase();
    b = b.toLowerCase();
    
    for (int i = 0; i < b.length(); i++) {
        a = a.replaceFirst(String.valueOf(b.charAt(i)), "");
    }

    return a.isEmpty() ? true : false;
}

What about this solution guys?

package chapter01.exercise_18;

public class CheckTwoStringsAnagram {

    public static void main(String[] args) {
        var one = "geeksforgeeks";
        var two = "forgeeksgeeks";
        var areAnagrams = checkIfTwoStringsAreAnagrams(one, two);
        System.out.format("The strings \"%s\" and \"%s\" are anagrams? %b", one, two, areAnagrams);
    }

    private static boolean checkIfTwoStringsAreAnagrams(final String one, final String two) {
        var oneWithoutSpacesAndLowerCase = one.replaceAll("\\s", "").toLowerCase();
        var twoWithoutSpacesAndLowerCase = two.replaceAll("\\s", "").toLowerCase();
        var countOneCharacters = oneWithoutSpacesAndLowerCase.chars().sum();
        var countTwoCharacters = twoWithoutSpacesAndLowerCase.chars().sum();
        return !oneWithoutSpacesAndLowerCase.equals(twoWithoutSpacesAndLowerCase)
                && countOneCharacters == countTwoCharacters;
    }

}

A much more simple solution:

private static boolean isAnagram(String a, String b) {
    if (a.length() != b.length()) {
        return false;
    }
    a = a.toLowerCase();
    b = b.toLowerCase();
    
    for (int i = 0; i < b.length(); i++) {
        a = a.replaceFirst(String.valueOf(b.charAt(i)), "");
    }

    return a.isEmpty() ? true : false;
}

Is more simple than everything 👯

static boolean isAnagram(String a, String b) {
        // Complete the function
        a = a.toLowerCase();
        b = b.toLowerCase();
        int aVal = 0, bVal = 0;
        
        
        if ( a.length() != b.length() )
            return false;
        for ( int i = 0; i < a.length(); i++ ) {
            aVal += (int)a.charAt(i)*(int)a.charAt(i);
            bVal += (int)b.charAt(i)*(int)b.charAt(i);
        }
        
        return aVal == bVal ? true : false;
    }

seems this is more simpler...

import java.util.Scanner;

public class Solution {

static boolean isAnagram(String a, String b) {
    // Complete the function
    if(a.length() == b.length()){
        
    
        a=a.toUpperCase();
        b=b.toUpperCase();
        char[] ch1 = a.toCharArray();
        char[] ch2 = b.toCharArray();
        char temp;
        for(int i=0;i<ch1.length;i++){
            for(int j=i+1;j<ch1.length;j++){
                if(ch1[i]>ch1[j]){
                    temp =  ch1[i];
                    ch1[i] =ch1[j];
                    ch1[j] = temp; 
                }
            }
        }
        for(int i=0;i<ch2.length;i++){
            for(int j=i+1;j<ch2.length;j++){
                if(ch2[i]>ch2[j]){
                    temp =  ch2[i];
                    ch2[i] =ch2[j];
                    ch2[j] = temp; 
                }
            }
        }
        //System.out.println(ch1);
        //System.out.println(ch2);
        
        //int[] charcounta = new int[ch1.length];
        for (int i = ch1.length - 1; i >= 0; i--)   
        {  
            if(ch1[i]!=ch2[i]){
                return false;
            }else{
                continue;
            }
            
        }  
        return true;
    }
    return false;
}

public static void main(String[] args) {

    Scanner scan = new Scanner(System.in);
    String a = scan.next();
    String b = scan.next();
    scan.close();
    boolean ret = isAnagram(a, b);
    System.out.println( (ret) ? "Anagrams" : "Not Anagrams" );
}

}