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String to Integer (atoi)
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# https://leetcode.com/problems/string-to-integer-atoi/ | |
class Solution: | |
def convert_char_to_int(self, digit_as_char: str) -> int | None: | |
if digit_as_char == '0': | |
return 0 | |
elif digit_as_char == '1': | |
return 1 | |
elif digit_as_char == '2': | |
return 2 | |
elif digit_as_char == '3': | |
return 3 | |
elif digit_as_char == '4': | |
return 4 | |
elif digit_as_char == '5': | |
return 5 | |
elif digit_as_char == '6': | |
return 6 | |
elif digit_as_char == '7': | |
return 7 | |
elif digit_as_char == '8': | |
return 8 | |
elif digit_as_char == '9': | |
return 9 | |
else: | |
return None | |
def is_valid_numeric_character(self, s: str): | |
return self.convert_char_to_int(s) is not None | |
def clamp_int_value(self, i: int) -> int: | |
if i < (-2)**31: | |
return (-2)**31 | |
elif i > 2**31 - 1: | |
return 2**31 - 1 | |
else: | |
return i | |
def convert_string_to_int(self, number_as_str: str) -> int: | |
# number_as_str = '42' | |
number = 0 | |
num_digits = len(number_as_str) | |
for i in range(len(number_as_str)): | |
current_digit = number_as_str[i] | |
digit_converted = self.convert_char_to_int(current_digit) | |
number += 10**(num_digits-i-1) * digit_converted | |
return number | |
def myAtoi(self, s: str) -> int: | |
leading_whitespaces = True | |
leading_sign = True | |
sign = 1 | |
number_substring = '' | |
for c in s: | |
if c == ' ' and leading_whitespaces: | |
continue | |
elif c == '-' and leading_sign: | |
leading_whitespaces = False | |
leading_sign = False | |
sign = -1 | |
elif c == '+' and leading_sign: | |
leading_whitespaces = False | |
leading_sign = False | |
sign = 1 | |
elif self.is_valid_numeric_character(c): | |
leading_whitespaces = False | |
leading_sign = False | |
number_substring += c | |
else: | |
break | |
return self.clamp_int_value(sign * self.convert_string_to_int(number_substring)) |
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