Last active
December 27, 2015 07:49
-
-
Save Abreto/7291649 to your computer and use it in GitHub Desktop.
Wikioi Problem 1004
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
/* Wikioi - Problem 1004. */ | |
#include <stdio.h> | |
#include <stdlib.h> | |
#include <limits.h> | |
#define QUEUE_MAXSIZE 65535 | |
#define QUEUE_DELTASZ 65535 | |
#define BOARD_SIZE 4 | |
typedef long long llint; | |
typedef struct _status | |
{ | |
char board[BOARD_SIZE][BOARD_SIZE]; | |
int x[4],y[4]; /* 0-1 for now, 2-3 for pre. 2 to 0, 3 to 1. */ | |
llint nsteps; | |
char player; /* 'B' for black, 'W' for white. */ | |
}status, *p_status; | |
void | |
stacpy(p_status dest, status src) | |
{ | |
int i = 0, j = 0; | |
for(i = 0;i < BOARD_SIZE;++i) | |
for(j = 0;j < BOARD_SIZE;++j) | |
{ | |
dest->board[i][j] = src.board[i][j]; | |
} | |
for(i = 0;i < 4;++i) | |
{ | |
dest->x[i] = src.x[i]; | |
dest->y[i] = src.y[i]; | |
} | |
dest->nsteps = src.nsteps; | |
dest->player = src.player; | |
} | |
typedef struct _queue | |
{ | |
llint size; | |
p_status data; | |
int head, tail; | |
}queue, *p_queue; | |
void | |
initq(p_queue q) | |
{ | |
q->size = QUEUE_MAXSIZE + 1; | |
q->data = (p_status)malloc(q->size * sizeof(status)); | |
q->head = q->tail = 0; | |
} | |
void | |
clear(p_queue q) | |
{ | |
q->head = q->tail = 0; | |
} | |
void | |
destory(p_queue q) | |
{ | |
free(q->data); | |
} | |
int | |
is_empty(queue q) | |
{ | |
return (q.head == q.tail); | |
} | |
int | |
is_full(queue q) | |
{ | |
return ( (q.tail+1)%(q.size) == q.head ); | |
} | |
void | |
greatenq(p_queue q) | |
{ | |
int i = 0; | |
llint nsize = q->size + QUEUE_DELTASZ; | |
p_status ndata = (p_status)malloc(nsize * sizeof(status)); | |
for(i = q->head;i%(q->size) != q->tail;++i) | |
ndata[i-q->head] = q->data[i%(q->size)]; | |
q->tail = i-q->head; | |
q->head = 0; | |
free(q->data); | |
q->data = ndata; | |
q->size = nsize; | |
} | |
void | |
enq(p_queue q, status s) | |
{ | |
if( is_full(*q) ) | |
greatenq(q); | |
stacpy(&(q->data[q->tail]), s); | |
q->tail = (q->tail+1)%(q->size); | |
} | |
void | |
deq(p_queue q, p_status s) | |
{ | |
if( is_empty(*q) ) | |
return ; | |
stacpy(s, q->data[q->head]); | |
q->head = (q->head+1)%(q->size); | |
} | |
int | |
check(status s) | |
{ | |
int isok = 1; | |
int i = 0, j = 0; | |
for(i = 0;i < 4;i++) | |
{ | |
isok = 1; | |
for(j = 1;j < 4;++j) | |
if( s.board[i][j] != s.board[i][j-1] ) | |
{ | |
isok = 0; | |
break; | |
} | |
if( isok ) | |
return 1; | |
} | |
for(j = 0;j < 4;++j) | |
{ | |
isok = 1; | |
for(i = 1;i < 4;++i) | |
if( s.board[i][j] != s.board[i-1][j] ) | |
{ | |
isok = 0; | |
break; | |
} | |
if( isok ) | |
return 1; | |
} | |
isok = 1; | |
for(i = 1;i < 4;++i) | |
if( s.board[i][i] != s.board[i-1][i-1] ) | |
{ | |
isok = 0; | |
break; | |
} | |
if( isok ) | |
return 1; | |
isok = 1; | |
for(i = 1;i < 4;++i) | |
if( s.board[i][3-i] != s.board[i-1][4-i] ) | |
{ | |
isok = 0; | |
break; | |
} | |
if(isok) | |
return 1; | |
return 0; | |
} | |
int | |
main(void) | |
{ | |
int i = 0, j = 0, nw = 0; | |
queue q; | |
status initialb; | |
int di[4] = {-1,0,1,0}, dj[4] = {0,-1,0,1}; | |
llint min = 1<<31-1; | |
for(i = 0;i < 4;++i) | |
{ | |
for(j = 0;j < 4;++j) | |
{ | |
scanf("%c", &( initialb.board[i][j] )); | |
if( 'O' == initialb.board[i][j] ) | |
{ | |
initialb.x[nw] = i; | |
initialb.y[nw] = j; | |
++nw; | |
} | |
} | |
getchar(); | |
} | |
/* bfs. */ | |
initq(&q); | |
initialb.nsteps = 0; | |
initialb.x[2] = initialb.x[3] = initialb.y[2] = initialb.y[3] = -1; | |
initialb.player = 'B'; | |
enq(&q, initialb); | |
initialb.player = 'W'; | |
enq(&q, initialb); | |
while( 0 == is_empty(q) ) | |
{ | |
status cur, tmp; | |
int o = 0, d = 0; | |
int ti = 0, tj = 0; | |
deq(&q, &cur); | |
if( check(cur) ) | |
{ | |
if( cur.nsteps < min ) | |
min = cur.nsteps; | |
if( cur.nsteps - min > 2 ) | |
break; | |
} | |
for(o = 0;o < 2;++o) | |
{ | |
for(d = 0;d < 4;++d) | |
{ | |
ti = cur.x[o] + di[d]; | |
tj = cur.y[o] + dj[d]; | |
if( ti < 0 || tj < 0 || ti > 3 || tj > 3 ) /* out of board. */ | |
continue; | |
if( ti == cur.x[o+2] && tj == cur.y[o+2] ) /* it refers to going back. */ | |
continue; | |
if( cur.board[ti][tj] != cur.player ) /* not on his turn. */ | |
continue; | |
/* now enq it. */ | |
stacpy(&tmp, cur); | |
tmp.board[tmp.x[o]][tmp.y[o]] = tmp.board[ti][tj]; | |
tmp.board[ti][tj] = 'O'; | |
tmp.x[o+2] = tmp.x[o]; | |
tmp.y[o+2] = tmp.y[o]; | |
tmp.x[o] = ti; | |
tmp.y[o] = tj; | |
++ (tmp.nsteps); | |
tmp.player = ('B' == tmp.player)?('W'):('B'); | |
enq(&q, tmp); | |
} | |
} | |
} | |
printf("%lld\n", min); | |
return 0; | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment