CrossUITesting-CodedUIScreenQuery.cs

public AppResult[] Query(string marked)
{
    try
    {
        var control = _screenDictionary
            .FindControl(_window.FriendlyName, () => marked);
        return new AppResult[]
        {
            new WindowsAppResult(control)
        };
    }
    catch (Exception ex)
    {
        Console.WriteLine(ex);
        return null;
    }
}