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November 18, 2018 00:31
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Given a binary tree, design an algorithm which creates a linked list of all the nodes at each depth.
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/* | |
List of depths: Given a binary tree, design an algorithm which creates a linked list of all the nodes | |
at each depth (eg if you have a tree with depth D, you'll have D linked lists.) | |
*/ | |
interface DepthQueue<T> { | |
depth: number, | |
node: T | |
} | |
function listOfDepths<T>(head: BinaryNode<T>) { | |
const listMap = new Map() | |
const queue = new MyQueue<DepthQueue<BinaryNode<T>>>() | |
listMap.set(0, new LinkedListNode(head)) | |
addChildrenToQueue(head, 1, queue) | |
while (!queue.isEmpty()) { | |
const { node, depth } = queue.remove().data | |
if (!listMap.get(depth)) { | |
listMap.set(depth, new LinkedListNode(node)) | |
} else { | |
listMap.get(depth).push(node) | |
} | |
addChildrenToQueue(node, depth + 1, queue) | |
} | |
return listMap | |
} | |
function addChildrenToQueue<T>(node: BinaryNode<T>, depth: number, queue: MyQueue<DepthQueue<BinaryNode<T>>>) { | |
if (!node) return null | |
if (node.leftChild) { | |
queue.add({ | |
depth, | |
node: node.leftChild | |
}) | |
} | |
if (node.rightChild) { | |
queue.add({ | |
depth, | |
node: node.rightChild | |
}) | |
} | |
} | |
// given a sorted (increasing order) array with unique integer elements, write an algorithm to create a binary search tree with minial height. | |
class BinaryNode<T> { | |
data: T | |
leftChild: BinaryNode<T> | |
rightChild: BinaryNode<T> | |
constructor(data: T) { | |
this.data = data | |
} | |
} | |
class LinkedListNode<T> { | |
next: LinkedListNode<T> | |
data: T | |
constructor(node: BinaryNode<T>) { | |
if (!node) return | |
this.data = node.data | |
} | |
push = (newTail: LinkedListNode<T>) => { | |
let node: LinkedListNode<T> = this | |
while (node.next != null) { | |
node = node.next | |
} | |
node.next = newTail | |
} | |
} | |
// given a sorted (increasing order) array with unique integer elements, write an algorithm to create a binary search tree with minial height. | |
class BinaryNode<T> { | |
data: T | |
leftChild: BinaryNode<T> | |
rightChild: BinaryNode<T> | |
constructor(data: T) { | |
this.data = data | |
} | |
} | |
function buildTree(lst: number[]) { | |
if (!lst || lst.length === 0) return null | |
if (lst.length === 1) return new BinaryNode(lst[0]) | |
const medianIndex = Math.ceil((lst.length - 1) / 2) | |
const node = new BinaryNode(lst[medianIndex]) | |
node.leftChild = buildTree(lst.slice(0, medianIndex)) | |
node.rightChild = buildTree(lst.slice(medianIndex + 1, lst.length)) | |
return node | |
} | |
const myTree = buildTree([1,2,3,4,5,6,7,8]) | |
console.log(listOfDepths(myTree)) |
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