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@Amli
Created April 23, 2014 13:13
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DELIMITER ;
DROP FUNCTION IF EXISTS urlencode;
DELIMITER |
CREATE FUNCTION URLENCODE(str VARCHAR(4096) CHARSET utf8) RETURNS VARCHAR(4096) CHARSET utf8
DETERMINISTIC
CONTAINS SQL
BEGIN
-- the individual character we are converting in our loop
-- NOTE: must be VARCHAR even though it won't vary in length
-- CHAR(1), when used with SUBSTRING, made spaces '' instead of ' '
DECLARE sub VARCHAR(1) CHARSET utf8;
-- the ordinal value of the character (i.e. ñ becomes 50097)
DECLARE val BIGINT DEFAULT 0;
-- the substring index we use in our loop (one-based)
DECLARE ind INT DEFAULT 1;
-- the integer value of the individual octet of a character being encoded
-- (which is potentially multi-byte and must be encoded one byte at a time)
DECLARE oct INT DEFAULT 0;
-- the encoded return string that we build up during execution
DECLARE ret VARCHAR(4096) DEFAULT '';
-- our loop index for looping through each octet while encoding
DECLARE octind INT DEFAULT 0;
IF ISNULL(str) THEN
RETURN NULL;
ELSE
SET ret = '';
-- loop through the input string one character at a time - regardless
-- of how many bytes a character consists of
WHILE ind <= CHAR_LENGTH(str) DO
SET sub = MID(str, ind, 1);
SET val = ORD(sub);
-- these values are ones that should not be converted
-- see http://tools.ietf.org/html/rfc3986
IF NOT (val BETWEEN 48 AND 57 OR -- 48-57 = 0-9
val BETWEEN 65 AND 90 OR -- 65-90 = A-Z
val BETWEEN 97 AND 122 OR -- 97-122 = a-z
-- 45 = hyphen, 46 = period, 95 = underscore, 126 = tilde
val IN (45, 46, 95, 126)) THEN
-- This is not an "unreserved" char and must be encoded:
-- loop through each octet of the potentially multi-octet character
-- and convert each into its hexadecimal value
-- we start with the high octect because that is the order that ORD
-- returns them in - they need to be encoded with the most significant
-- byte first
SET octind = OCTET_LENGTH(sub);
WHILE octind > 0 DO
-- get the actual value of this octet by shifting it to the right
-- so that it is at the lowest byte position - in other words, make
-- the octet/byte we are working on the entire number (or in even
-- other words, oct will no be between zero and 255 inclusive)
SET oct = (val >> (8 * (octind - 1)));
-- we append this to our return string with a percent sign, and then
-- a left-zero-padded (to two characters) string of the hexadecimal
-- value of this octet)
SET ret = CONCAT(ret, '%', LPAD(HEX(oct), 2, 0));
-- now we need to reset val to essentially zero out the octet that we
-- just encoded so that our number decreases and we are only left with
-- the lower octets as part of our integer
SET val = (val & (POWER(256, (octind - 1)) - 1));
SET octind = (octind - 1);
END WHILE;
ELSE
-- this character was not one that needed to be encoded and can simply be
-- added to our return string as-is
SET ret = CONCAT(ret, sub);
END IF;
SET ind = (ind + 1);
END WHILE;
END IF;
RETURN ret;
END;
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DELIMITER ;
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