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| """ | |
| Write a program that repeatedly prompts a user for integer numbers until the user enters 'done'. Once 'done' is entered, print out the largest and smallest of the numbers. If the user enters anything other than a valid number catch it with a try/except and put out an appropriate message and ignore the number. | |
| """ | |
| largest = None | |
| smallest = None | |
| while True: | |
| try: | |
| num = raw_input("Enter a number: ") | |
| if num == 'done': | |
| break; | |
| n = int(num) | |
| largest = num if largest < num or largest == None else largest | |
| smallest = num if smallest > num or smallest == None else smallest | |
| except: | |
| print "Invalid input" | |
| print "Maximum number is ", largest | |
| print "Minimum number is ", smallest |
The below worked for me!
largest = None
smallest = None
while True:
num = input('Enter number: ')
if num == 'done':
break
try:
inum = int(num)
except:
print('Invalid input')
continue
if largest is None or inum > largest:
largest = inum
elif smallest is None or inum < smallest:
smallest = inum
print ("Maximum is",largest)
print ("Minimum is",smallest)
largest = None
smallest = None
while True:
try:
num = raw_input("Enter a number: ")
if num == "done":
break
num = int(num)
if largest is None or largest < num:
largest = num
elif smallest == None or smallest > num:
smallest = num
except:
print("Invalid input")
continue
#print(num)
Working
largest = None
smallest = None
while True:
num = input("Enter a number: ")
if num == "done":
break
try:
n = int(num)
if largest is None or n > largest:
largest = n
elif smallest is None or n < smallest:
smallest = n
except Exception:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)
Invalid input
Maximum is 10
Minimum is 2
Please help Unable to get correct Output
Hey PersonalDvbt22 it might serve you well to separate the try/except functions from the conditional loop for the smallest and largest. Remember that the try should only be inputted for items that are absolute. Try this instead:
Working
largest = None
smallest = None
while True:
num = raw_input("Enter a number: ")
if num == "done" : break
try:
num = int(num)
except:
print("Invalid input")
continue
if largest is None:
largest = num
elif num > largest:
largest = num
if smallest is None:
smallest = num
elif num < smallest:
smallest = num
print("Maximum is", largest)
print("Minimum is", smallest)
In need help
list = []
while True:
try:
number = input("Enter a number:")
if number == 'done':
break
converted = int(number)
list.append(converted)
maximum = max(list)
minimum = min(list)
except:
print("Invalid input")
print("Maximum is",maximum)
print("Minimum is",minimum)
largest = 0
smallest = 0
while True:
try:
num = raw_input("Enter a number: ")
if num == "done":
break
num = int(num)
if largest == 0 or largest < num:
largest = num
elif smallest == 0 or smallest > num:
smallest = num
except:
print("Invalid input")
print("Maximum is", largest)
print("Minimum is", smallest)
encounering invalid error 5 times anyone can explain why?
I think your if condition is something wrong.
largest = None
smallest = None
while True:
try:
num = raw_input("Enter a number: ")
if num == "done":
break
n = int(num)
if largest is None or n > largest:
largest = n
elif smallest is None or n < smallest:
smallest = n
except ValueError:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)
largest = None
smallest = None
fig = True # will help to initialize largest and smallest from None to a known number
while True:
num = input("ENter a number: ")
if num == "done":
break
try:
num = int(num)
if fig is True:
largest = num
smallest = num
fig = False
else:
if (num >= largest):
largest = num
elif (num <= smallest):
smallest = num
except:
print("Invalid input")
print ("Maximum", largest)
print ("Minimum", smallest)
why am i getting this feedback
largest = None
smallest = None
while True:
try:
num = input("Enter a number: ")
if num == 'done':
break
n = int(num)
if largest is None or n > largest:
largest = n
elif smallest is None or n < smallest:
smallest = n
except:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)
largest = None smallest = None while True: num = input("Enter a number: ") if num == 'done': break try: n = int(num) except: print('Invalid input') continue if largest is None or largest < n: largest = n elif smallest is None or smallest > n: smallest = n elif n < smallest: smallest = n print('Maximum is',largest) print('Minimum is',smallest)Thanks a lot Man It worked out
Quick question why does this work when comparing to a NoneType value but when comparing it directly won't work? I understand they are different types of data and can't be compared but why adding that extra "is None" makes it work.
Hi man, try this code
numList = []
while True:
try:
num = input("Enter a number: ")
if num == 'done':
break
n = int(num)
if n != 'done':
Value = n
numList.append(Value)
smallest = min(numList)
largest = max(numList)
except:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)
Hi man, try this code
numList = [] while True: try: num = input("Enter a number: ") if num == 'done': break n = int(num) if n != 'done': Value = n numList.append(Value) smallest = min(numList) largest = max(numList) except: print("Invalid input") continue print("Maximum is", largest) print("Minimum is", smallest)
You can try this:
num_set = []
def check_num():
while True:
try:
num = input("Enter a number or type 'done': ")
lower_num = num.lower()
if lower_num == "done":
return
isinstance(num, int)
num = int(num)
num_set.append(num)
except:
print("Invalid input")
def check_size():
if not num_set:
return
else:
print("Maximum is", max(num_set))
print("Minimum is", min(num_set))
check_num()
check_size()
This should work
largest = None
smallest = None
while True :
number = input('Enter Number:')
if number == 'done' :
break
try:
num = int(number)
except:
print('Invalid input')
continue
if smallest is None :
smallest = num
elif num < smallest :
smallest = num
if largest is None :
largest = num
elif num > largest :
largest = num
print('Maximum is', largest)
print('Minimum is', smallest)```
largest = None
smallest = None
#MOST NEEDED COMMAND AS IT MADE ME CONFUSED TOO
#print("input Done to end loop")
while True:
try:
num= input("input number")
if num == "done":
break
num = int(num)
if largest is None or num > largest:
largest = num
elif smallest is None or num < smallest:
smallest = num
except:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)
**smlest = None
lrgest = None
while True:
num = input('ENTER THE NUMBER :')
if num == 'done':
break
try:
n=int(num)
except:
print('Invalid input')
if smlest is None:
smlest=n
elif n<smlest:
smlest=n
elif lrgest is None:
lrgest=n
elif n>lrgest:
lrgest=n
print('Maximum is',lrgest)
print('Minimum is',smlest)**
largest = None
smallest = None
while True :
try :
num = raw_input("Enter number")
if num == "done" :
break
num = int(num)
if largest is None :
largest = num
elif largest < num :
largest = num
if smallest is None:
smallest = num
elif smallest > num :
smallest = num
except :
print("Invalid input")
continue
print("Maximun is", largest)
print("Mininimum is", smallest)
""" Write a program that repeatedly prompts a user for integer numbers until the user enters 'done'. Once 'done' is entered, print out the largest and smallest of the numbers. If the user enters anything other than a valid number catch it with a try/except and put out an appropriate message and ignore the number.
My inputs: 7, 2, bob, 10, and 4
My outputs: Invalid input, 10, 10
"""
largest = None
smallest = None
while True:
try:
num = input("Enter a number: ")
""" In order to avoid the type error of the comparison between integer and NoneType you must 'cast' the integer type in the if/else statement. `Otherwhise` the first time you would compare an integer with a nonetype. """
largest = int(num) if largest == None or int(largest) < int(num) else largest
smallest = int(num) if smallest == None or int(smallest) > int(num) else smallest
except:
""" You need to enter here only if the command "int(num)" throws an error. Then, you ask if num is a string with the value 'done' in order to break the loop """
if str(num) == 'done':
break;
print("Invalid input")
print("Maximum is", largest)
print("Minimum is", smallest)
Check out my answer:
"""5.2 Write a program that repeatedly prompts a user for integer numbers
until the user enters 'done'. Once 'done' is entered,
print out the largest and smallest of the numbers.
If the user enters anything other than a valid number catch it
with a try/except and put out an appropriate message and ignore the number.
Enter 7, 2, bob, 10, and 4 and match the output below."""
# create an empty list where the user input will be stored.
num_list = []
while True:
userNumber = input("Please enter a number. Type 'Done' if you want to stop: ")
if userNumber == 'Done':
break
try:
userNumberint = int(userNumber)
except:
print("Invalid input")
continue
# the user's input will be appended in num_list.
num_list.append(userNumberint)
# added an if statement to check if the list is empty.
if bool(num_list):
# If the list is not empty, it will print the max and min numbers.
print(f"Maximum is {max(num_list)}")
print(f"Minimum is {min(num_list)}")
# If the list is empty, it will print the below statement.
else:
print("Please type some numbers.")
this code work for me
create an empty list where the user input will be stored.
num_list = []
while True:
userNumber = input("Please enter a number. Type 'Done' if you want to stop: ")
if userNumber == 'Done':
break
try:
userNumberint = int(userNumber)
except:
print("Invalid input")
continue
# the user's input will be appended in num_list.
num_list.append(userNumberint)
added an if statement to check if the list is empty.
if bool(num_list):
# If the list is not empty, it will print the max and min numbers.
print(f"Maximum is {max(num_list)}")
print(f"Minimum is {min(num_list)}")
If the list is empty, it will print the below statement.
else:
print("Please type some numbers.")
largest = None
smallest = None
while True:
num = input("Enter a number: ")
if num == "done":
break;
try:
n = int(num)
if largest is None or n > largest:
largest = n
elif smallest is None or n < smallest:
smallest = n
except:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)
#My solution: Indentation is important and remembering when inputting the numbers don't space by accident.
No need to add space after is in the print Function because the input function would add the space before.
What is the role of 'continue' statement in the 'except:' part of the code after the print statement?
largest = None
smallest = None
while True:
try:
num = input("Enter a number: ")
if num == "done":
break
num = int(num)
if largest is None or num > largest:
largest = num
elif smallest is None or num < smallest:
smallest = num
except:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)
largest = None
smallest = None
while True:
num = raw_input("Enter a number: ")
if num == "done" : break
try:
num = int(num)
except:
print("Invalid input")
continue
if largest is None:
largest = num
elif num > largest:
largest = num
if smallest is None:
smallest = num
elif num < smallest:
smallest = num
print("Maximum is", largest)
print("Minimum is", smallest)
@kreeztoph hi ur code seems fine but u have used list keyword instead name it list1 /list2 and try it .
largest = None
smallest = None
List_collector=[]
while True:
try:
num = input("Enter a number: ")
if num == 'done':
break
n = int(num)
List_collector.append(n)
largest=max(List_collector)
smallest=min(List_collector)
except:
print("Invalid input")
continue
print("Maximum is", largest)
print("Minimum is", smallest)