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July 5, 2018 20:34
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Just an alphabet.
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var alphabet=[ | |
{letter:"a",consonant:false}, | |
{letter:"b",consonant:true}, | |
{letter:"c",consonant:true}, | |
{letter:"d",consonant:true}, | |
{letter:"e",consonant:false}, | |
{letter:"f",consonant:true}, | |
{letter:"g",consonant:true}, | |
{letter:"h",consonant:true}, | |
{letter:"i",consonant:false}, | |
{letter:"j",consonant:true}, | |
{letter:"k",consonant:true}, | |
{letter:"l",consonant:true}, | |
{letter:"m",consonant:true}, | |
{letter:"n",consonant:true}, | |
{letter:"o",consonant:false}, | |
{letter:"p",consonant:true}, | |
{letter:"q",consonant:true}, | |
{letter:"r",consonant:true}, | |
{letter:"s",consonant:true}, | |
{letter:"t",consonant:true}, | |
{letter:"u",consonant:false}, | |
{letter:"v",consonant:true}, | |
{letter:"w",consonant:true}, | |
{letter:"x",consonant:true}, | |
{letter:"y",consonant:false}, | |
{letter:"z",consonant:true} | |
]; |
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I was using this for generating random strings, but this is incorrect because consonants vary a lot, if we were going to look for consonants then we should look it as a group of letters to confirm that which could be the correct way of doing it. I knew this but whatever.