Convert C++ headers to boilerplate source files

header2source.py

import sys
import re
import os


header_filename = sys.argv[1]
if not header_filename:
	raise "No filename given"


header_basename = os.path.basename(header_filename)
class_name = None
namespace_name = None

print("#include \"" + header_basename + "\"")
print("")

with open(header_filename) as f:
	for line in f:
		# Check for namespace
		r = re.match(r'\s*(namespace)\s+(\w+)', line)
		if r:
			namespace_name = r.group(2)
			print("namespace " + namespace_name + " {")
			print("")
		# Check for class
		r = re.match(r'\s*(class|struct)\s+(\w+)', line)
		if r:
			class_name = r.group(2)
		# Check for end of class
		r = re.match(r'};', line)
		if r:
			class_name = None
		# Check for function/method
		r = re.match(r' *(virtual +)?(.*?)([~\w]+)\((.*?)\) *(override)?;', line)
		if r:
			ret = r.group(2).strip()
			if ret and ret[-1] != "*":
				ret += " "
			method = r.group(3)
			if class_name:
				method = class_name + "::" + method
			args = r.group(4)
			print(ret + method + "(" + args + ") {")
			print("}")
			print("")


if namespace_name:
	print("} // namespace " + namespace_name)

print("")