meh.rb

require "benchmark"

def reverse number
  inverse = 0
  while number > 0
    inverse = inverse * 10 + (number % 10)
    number = number / 10
  end
  inverse
end

def is_palindrome_1? number
  number == reverse(number)
end

def is_palindrome_2? number
  number== number.reverse
end

1.upto(1000000) {|n| n.to_s}

puts Benchmark.measure {
  1.upto(1000000) do |n|
    n = n.to_s
    is_palindrome_1?(Integer(n))
  end
}

puts Benchmark.measure {
  1.upto(1000000) do |n|
    n = n.to_s
    is_palindrome_2?(n)
  end
}