Pure python replacement for ssh_copy_id

ssh_copy_id.py

import argparse
import sys
import os

def ssh_copy_id(host='localhost', ssh='ssh', keyfile='~/id_rsa.pub', sshopts=()):
    opts = ' '.join('-o ' + opt for opt in sshopts )
    cmd = 'cat %(keyfile)s | %(ssh)s %(opts)s %(host)s \'umask 077; mkdir -p .ssh; cat >> .ssh/authorized_keys\''
    os.system(cmd % locals())

if __name__ == "__main__":
    parser = argparse.ArgumentParser('ssh-copy-id')
    parser.add_argument('-e',
                        '--executable',
                        default = 'ssh')
    parser.add_argument('-o',
                        dest='sshopt',
                        action='append')
    parser.add_argument('-i',
                        '--identity-file',
                        default = '~/.ssh/id_rsa.pub')
    parser.add_argument('host')
    args = parser.parse_args(sys.argv[1:])
    ssh_copy_id(host=args.host, keyfile=args.identity_file, ssh=args.executable, sshopts=args.sshopt)