Java program for printing the matrix elements in Spiral Order

Spiral Matrix

    public static void main(String[] args) {
        
        String[][] spiral = new String[3][3]; 
        spiral[0][0] = "1";
        spiral[0][1] = "2";
        spiral[0][2] = "3";
        spiral[1][0] = "4";
        spiral[1][1] = "5";
        spiral[1][2] = "6";
        spiral[2][0] = "7";
        spiral[2][1] = "8";
        spiral[2][2] = "9";        
  
//        Uncomment this section, if you want to get input dynamically.
//        for(int i=0; i<spiral.length; i++){
//            for(int j=0; j<spiral.length; j++){
//                Scanner sc = new Scanner(System.in);
//                sc.next();
//            }
//        }

        int rowStart, columnStart, rowEnd, columnEnd;
        rowStart = columnStart = 0;
        rowEnd = columnEnd = spiral.length - 1;
        
        while(rowStart <= rowEnd && columnStart <= columnEnd)
        {
            int i = rowStart, j = columnStart;
            
            for(j = columnStart; j<=columnEnd; j++)
                System.out.println(spiral[i][j]);
            
            for(i = rowStart+1, j--; i<=rowEnd; i++)
                System.out.println(spiral[i][j]);
            
            for(j = columnEnd-1, i--; j>=columnStart; j--)
                System.out.println(spiral[i][j]);
            
            for(i = rowEnd-1, j++; i>=rowStart+1; i--)
                System.out.println(spiral[i][j]);
            
            rowStart++; columnStart++; rowEnd--; columnEnd--;
        }        
    }