Number of Vowels

gistfile1.txt

Assumptions:

I am assuming that we are differentiating between letters that represent consonants and vowels and not between 
vowel and consonant sounds. The letter "y" is not always considered a vowel and so I will not be counting it, nor will I 
be counting the letter "w".

Test Cases:

"Hello World"//3
"Downton Abbey"//4
"Flooded doors don't flinch dumbly."//8
"Everyone Is Okay."//7

Approach:

A variable called "count" will be created and it will take an integer. I will create a for loop that iterates over all of the 
letters in the string. I will create a switch statement within the for loop that tests for vowels. For each vowel, count will 
plus equal one. I will then return count.

func numberOfVowels(string:String) -> Int {
    
    //I lowercase the string to simplify the switch statement.
    let myString = string.lowercased()
    
    //This variable will count the vowels, it is the Int that I will be returning.
    var count : Int = 0

    //This for loop iterates over all of the letters in the lowercased string, the switch statements checks each letter to see if it is a vowel.
    for letter in myString {
        switch letter {
        case "a":
            count += 1
        case "e":
            count += 1
        case "i":
            count += 1
        case "o":
            count += 1
        case "u":
            count += 1
        default:
            break
        }
    }
   return count

Looks great Austin! You've definitely got a working solution and I can clearly see your thought process in the comments. You are missing a closing curly brace at the end, but I am assuming that was a transcription error. My only other suggestion would be that since your code is the same in all the cases, you could condense a little by putting them all on one line like so: case "a", "e", "i", "o", "u":