Python script to check if there are any `corgiorgy` available from a list of words

orgyparty-checker.py

# DEPENDS: Selenium Driver
# NOTE: PhantomJS must be present in your PATH

from selenium import webdriver
browser_engine = webdriver.PhantomJS()

main_url_ = "http://"
main_url__ = ".corgiorgy.com"

words = "very through just form much great think say help low line before turn cause same mean differ move right boy old too does tell sentence set three want air well also play small end put home read hand port large spell add even land here must big high such follow act why ask men change went light kind off need house picture try us again animal point mother world near build self earth father head stand own page should country found answer school grow study still learn plant cover food sun four thought keep eye never last door between city tree cross since hard start might story saw far sea draw left late run don't while press close night real life few"
words_list = words.split()

url = ""
for word in words_list:
    url = main_url_ + word + main_url__
    browser_engine.get(url)
    sauce = browser_engine.page_source

    if "Party not found!" in sauce:
        print("[+] The word [" + word + "] is available!")
    else:
        print("[+] The word [" + word + "] is already taken.")

print("Done!")

#EXAMPLE OUTPUT:
#[+] The Word [us] is already taken.
#[+] The Word [men] is already taken.
#[+] The Word [ask] is already taken.
#[+] The Word [why] is already taken.
#[+] The Word [eye] is already taken.
#[+] The Word [big] is already taken.
#[+] The Word [boy] is already taken.
#[+] The Word [old] is already taken
# ....