Created
February 2, 2012 11:17
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{ notes: " " | |
name: MAS1341 20122013 CBA2a_1 | |
percentPass: 50 | |
shuffleQuestions: false | |
rulesets:{ | |
std:[all,fractionNumbers, !collectNumbers,!noLeadingMinus] | |
} | |
navigation: { | |
allowregen: true | |
showfrontpage: false | |
reverse: true | |
browse: true | |
} | |
feedback: { | |
showtotalmark: true | |
} | |
questions: [ | |
{ | |
name: MAS1341 20122013 CBA2a_1 | |
variables: { | |
r:"random(45..65)" | |
s:"round(r/10)" | |
d:"round(t/15)" | |
t1:"round(s*random(70..100)/100)" | |
t2:"t1" | |
t:"100-r" | |
u1:"round(d*random(70..100)/100)" | |
u2: "u1" | |
u3:"u1" | |
p0: "s" | |
p1: "p0+t1" | |
p2: "p1+t2" | |
p3: "r-p0-p1-p2" | |
p4: "t-p8-p7-p6-p5" | |
p5: "p6+u3" | |
p6: "p7+u2" | |
p7: "p8+u1" | |
p8: "d" | |
check: "p0+p1+p2+p3+p4+p5+p6+p7+p8" | |
n1:"0" | |
n2:"1" | |
n3:"2" | |
n4:"3" | |
n5:"4" | |
n6:"5" | |
n7:"6" | |
n8:"7" | |
n9:"8" | |
ecom:"(n1*p0+n2*p1+n3*p2+n4*p3+n5*p4+n6*p5+n7*p6+n8*p7+n9*p8)/100" | |
probexceed:"if(ecom>3,p4+p5+p6+p7+p8,if(ecom>4,p5+p6+p7+p8,if(ecom>5,p6+p7+p8,1-p0-p1-p2)))" | |
strexceed:"if(ecom>3,p4/100+'+'+p5/100+'+'+p6/100+'+'+p7/100+'+'+p8/100,if(ecom>4,p5/100+'+'+p6/100+'+'+p7/100+'+'+p8/100,if(ecom>5,p6/100+'+'+p7/100+'+'+p8/100,p3/100+'+'+p4/100+'+'+p5/100+'+'+p6/100+'+'+p7/100+'+'+p8/100)))" | |
idef:"'an'" | |
organisation:"'airline'" | |
period:"'day'" | |
activity:"'luggage handling'" | |
episodes:"'complaints'" | |
} | |
statement: """ | |
The probabilities that {idef} {organisation} will receive {episodes} per {period} about its {activity} are given by the following table: | |
<table border="3"> | |
<tr><td>Complaints</td><td>0</td><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td><td>8</td></tr> | |
<tr><td>Probability</td><td>$\var{p0/100}$</td><td>$\var{p1/100}$</td><td>$\var{p2/100}$</td><td>$\var{p3/100}$</td><td>$\var{p4/100}$</td><td>$\var{p5/100}$</td><td>$\var{p6/100}$</td><td>$\var{p7/100}$</td><td>$\var{p8/100}$</td></tr> | |
</table> | |
Answer the following two parts: | |
""" | |
parts: [ | |
{ | |
type: gapfill | |
prompt:""" | |
Find the expected number of {episodes} per {period}. | |
Answer to two decimal places | |
Expected number = [[0]]? | |
""" | |
gaps: [ | |
{type: numberentry | |
minvalue: "{ecom-0.01}" | |
maxvalue: "{ecom+0.01}" | |
marks: 2} | |
] | |
} | |
] | |
advice: """ | |
""" | |
} | |
] | |
} |
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