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Bl41r/codechallenge2.py

Created August 19, 2016 16:34
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code challenge 2
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codechallenge2.py
def smart_substr(in_str, terminate='...'):
if len(in_str) <= 30:
return in_str + terminate
else:
if in_str[30] != ' ':
return ' '.join(in_str[0:30].split()[:-1]) + terminate
else:
return in_str[0:30] + terminate
@cewing
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cewing commented Aug 19, 2016

what happens if the character at index 30 is the last character in a whole word?

@Bl41r
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Bl41r commented Aug 19, 2016

In [142]: smart_substr('12345678901234567890123 567890')
Out[142]: '12345678901234567890123 567890...'

@cewing
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cewing commented Aug 20, 2016

congratulations! you win the stump the chump award

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