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How to remove the luck factor from a luck based system.
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# -*- coding: utf-8 -*- | |
import time | |
import json | |
import urllib2 | |
import random | |
import subprocess | |
import datetime | |
from BeautifulSoup import BeautifulSoup | |
""" | |
https://marknad.studentbostader.se/widgets/?omraden=&egenskaper=SNABB&objektTyper=&actionId=&callback=jQuery17100253444043202945_1406813982377&widgets[]=koerochprenumerationer%40STD&widgets[]=objektfilter%40lagenheter&widgets[]=objektsortering%%40lagenheter&widgets[]=objektlista%%40lagenheter&widgets[]=pagineringgonew%%40lagenheter&widgets[]=pagineringlista%40lagenheter&widgets[]=pagineringgoold%40lagenheter&_=1406796622575 | |
_ attribute from normal requests: | |
1406796622575 | |
1406796904098 | |
Unix time in seconds: | |
1406796966 | |
_= unix timestamp ms | |
""" | |
curl = "https://marknad.studentbostader.se/widgets/?omraden=&egenskaper=%s&objektTyper=&actionId=&callback=&widgets[]=koerochprenumerationer%%40STD&widgets[]=objektfilter%%40lagenheter&widgets[]=objektsortering%%40lagenheter&widgets[]=objektlista%%40lagenheter&widgets[]=pagineringgonew%%40lagenheter&widgets[]=pagineringlista%%40lagenheter&widgets[]=pagineringgoold%%40lagenheter&_=%s" | |
def unix_time(): | |
return str(round(time.time()*1000)) | |
def alert(): | |
for i in range(20): | |
subprocess.Popen(["paplay", "/usr/share/sounds/KDE-Im-Message-In.ogg"]) | |
time.sleep(0.15) | |
def poll(): | |
res = urllib2.urlopen(curl % ("SNABB", unix_time(),)).read() | |
html = json.loads(res[1:len(res)-2])[u'html'][u'objektlista@lagenheter'] | |
soup = BeautifulSoup(html) | |
t = datetime.datetime.now() | |
if soup.find('div', {"class": "NoResult"}) is None: | |
print "[%s] Appartment found!!" % (t.strftime("%H:%M:%S"), ) | |
alert() | |
else: | |
print "[%s] Nope" % (t.strftime("%H:%M:%S"), ) | |
while True: | |
poll() | |
time.sleep(random.randrange(20, 30)) |
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