Given a stream of process ids associated with process start and finish actions, output the one process id which has not yet finished, or 0 if all processes are accounted for.

unique_process_ids.py

'''
Given a stream of process ids associated with process start and finish actions,
output the one process id which has not yet finished, or 0 if all processes are
accounted for.
'''

def finished_processes(ids):
    '''
    It would have been too easy to use the count() method in python - the solution
    would have been in a few lines of code only:

    ######
    def finished_processes(ids):
        count = 0
        for idd in ids:
            if ids.count(idd) == 1:
                count += 1
                print(idd)
        if count == 0:
            print 0
    ######

    Hence, I used another manual method.
    '''
    for idd in ids:
        count = 0
        for other_idd in ids:
            if idd == other_idd:
                count+=1
                if count == 2:
                    for i in range(count):
                        ids.remove(other_idd)
    if len(ids) == 1:
        print ids[0]
    else:
        print 0



if __name__ == '__main__':
    finished_processes([36,47,58,47,36])
    finished_processes([12,23,34,34,12,23])