BrendanNeufeld

//source: http://www.paulund.co.uk/output-php-data-in-browser-console

<?php
/**
 * Send debug code to the Javascript console
 */ 
function debug_to_console($data) {
    if(is_array($data) || is_object($data))
	{
		echo("<script>console.log('PHP: ".json_encode($data)."');</script>");