Created
August 6, 2018 01:37
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Median of Two Sorted Arrays
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class Solution: | |
def findMedianSortedArrays(self, nums1, nums2): | |
""" | |
:type nums1: List[int] | |
:type nums2: List[int] | |
:rtype: float | |
""" | |
if len(nums2) < len(nums1): | |
nums1, nums2 = nums2, nums1 | |
m, n = len(nums1), len(nums2) | |
imin, imax = 0, m | |
while imin <= imax: | |
i = int((imin + imax) / 2) | |
j = int((m + n + 1) / 2 - i) | |
if (i < m and nums2[j - 1] > nums1[i]): | |
imin = i + 1 | |
elif (i > 0 and nums1[i - 1] > nums2[j]): | |
imax = i - 1 | |
else: | |
maxLeft = 0 | |
if i == 0: | |
maxLeft = nums2[j - 1] | |
elif j == 0: | |
maxLeft = nums1[i - 1] | |
else: | |
maxLeft = max(nums1[i - 1], nums2[j - 1]) | |
if (m + n) % 2 == 1: | |
return maxLeft | |
minRight = 0 | |
if i == m: | |
minRight = nums2[j] | |
elif j == n: | |
minRight = nums1[i] | |
else: | |
minRight = min(nums1[i], nums2[j]) | |
return (maxLeft + minRight) / 2 | |
return 0 |
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