Created
November 24, 2020 07:57
-
-
Save CTimmerman/2f42879d8076ac01ddfffce9e6663d0f to your computer and use it in GitHub Desktop.
Euler's pentagonal formula
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
"""Euler's pentagonal formula, by Cees Timmerman, 2020-11-23. | |
https://www.youtube.com/watch?v=iJ8pnCO0nTY""" | |
import math | |
def get_lookback_index(x: int): | |
i = 0 | |
a = 0 | |
b = 1 | |
steps = [1] | |
while i < x-1: | |
i += 1 | |
if i % 2: | |
a += 1 | |
steps.append(a) | |
else: | |
b += 2 | |
steps.append(b) | |
return sum(steps) | |
def get_lookback_indexes(x: int): | |
results = [] | |
i = 1 | |
while True: | |
index = get_lookback_index(i) | |
if index >= x: break | |
results.append(index) | |
i += 1 | |
return results | |
def euler_pentagonal_number(x: int): | |
""" | |
>>> euler_pentagonal_number(0) | |
1 | |
>>> euler_pentagonal_number(1) | |
1 | |
>>> euler_pentagonal_number(666) | |
11956824258286445517629485 | |
""" | |
result = 1 | |
numbers = [1, 1] | |
for i in range(3, x+2): | |
result = 0 | |
looks = get_lookback_indexes(i) | |
#print(f"{i}th: {looks}") | |
for count, look in enumerate(looks): | |
factor = numbers[-look] | |
if count % 4 > 1: factor *= -1 | |
#print("factor", factor) | |
result += factor | |
#print(f"Number {i-1} is {result:}") | |
numbers.append(result) | |
return result | |
print("{:,}".format(euler_pentagonal_number(666))) |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment