Skip to content

Instantly share code, notes, and snippets.

What would you like to do?
Our model is
log(cell/ml) = alpha * (secchi stick depth) + intercept + Noise
However, our cell/mL comes from a noisy hemocytometer, and our
depth measured with the secchi stick is also noisy. Our goal is
still to infer alpha & intercept as well as possible, so we can
dump the hemocytometer.
import pymc3 as pm
squares_counted = 5
cells_counted = np.array([310, 148, 241])
depth_observed = np.array([1.4, 2.4, 1.7])
N = cells_counted.shape[0]
with pm.Model() as model:
alpha = pm.Normal("alpha", mu=0, sd=10)
# I need a test value here because of under/over flow problems.
intercept = pm.Normal("intercept", mu=0, sd=10, testval=15)
tau = pm.Exponential("tau", 0.1)
actual_depth = pm.Uniform("actual depth", lower=0, upper=10, shape=N)
depth = pm.Normal("depth observed", mu=actual_depth, sd=0.1, observed=depth_observed)
cells_conc = pm.Lognormal("cells/mL", mu=alpha * actual_depth + intercept, tau=tau, shape=N)
final_dilution_factor = 1
# the manufacturer suggests that depth of the chamber is 0.01cm ± 0.0004cm. Let's assume the worst and double the error.
# the length of the 5x5 square grid is 1mm = 0.1cm, so the volume is 0.01 * 0.1 * 0.1 = 0.0001, with error 0.1 * 0.1 * 0.0004 * 2
volume_of_chamber = pm.Normal("volume of chamber (mL)", mu=1e-4, sd=8e-6)
# why is Poisson justified? in my final shaker, I have cells_conc * final_dilution_factor * shaker3_volume number of cells
# I remove volume_of_chamber / shaker3_volume fraction of them, hence it's a binomial with very high count, and very low probability.
cells_visible = pm.Poisson("cells in visible portion", mu=cells_conc * final_dilution_factor * volume_of_chamber, shape=N)
number_of_counted_cells1 = pm.Binomial("number of counted cells", cells_visible, squares_counted/TOTAL_SQUARES, observed=cells_counted)
trace = pm.sample(18000, tune=14000)
pm.plot_posterior(trace, var_names=['cells/mL', 'alpha', "tau", "intercept"])
pm.summary(trace, var_names=['cells/mL', 'alpha', "tau", "intercept"])
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
You can’t perform that action at this time.