Grouptable Generator of Square

main.py

# The elements (corners) of the squae
elements = ["a", "b", "c", "d"]

ops = {
	'i':	{"a": "a", "b": "b", "c": "c", "d": "d"}, #identity
	'r':	{"a": "b", "b": "c", "c": "d", "d": "a"}, # rot 90
	's':	{"a": "c", "b": "d", "c": "a", "d": "b"}, # rot 180
	't':	{"a": "d", "b": "a", "c": "b", "d": "c"}, # rot 270

	'x':	{"a": "d", "b": "c", "c": "b", "d": "a"}, # mirror x
	'y':	{"a": "b", "b": "a", "c": "d", "d": "c"}, # mirror y
	'z':	{"a": "c", "b": "b", "c": "a", "d": "d"}, # mirror z
	'w':	{"a": "a", "b": "d", "c": "c", "d": "b"}  # mirror w
}


# resolve single argument
def resolve(input, op1, op2):
	return op2.get(op1.get(input))

# resolve every corner of square
def make(op1, op2):
	retDict = {}
	for e in elements:
		retDict[e] = op2.get(op1.get(e))
	
	return retDict

# find corresponding operation
def resolve(op1, op2):
	result = make(op1, op2)
	for op, comb in ops.items():
		if result == comb:
			return op

# print a nice table
def printAll():
	print(end=" |")
	[print(name, end=" ") for name in sorted(ops)]
	print()
	[print("---", end="") for name in sorted(ops)]
	print()
	for name0 in sorted(ops):
		print(name0, end="|")
		for name1 in sorted(ops):
			print(resolve(ops.get(name0), ops.get(name1)), end=" ")
		
		print()


printAll()