r/DailyProgrammer Rack Management 1

rack_management.py

#!usr/bin/env python3
"""
This script is the r/DailyProgrammer Easy Challenge #294 titled
Rack Management 1.
Author: Christopher Bilger
"""


def scrabble(rack_str, desired_str):
    """
    Function that will handle the scrabble rack_str as input and output a
    boolean of whether or not the rack_str contains the letters to make
    the desired_str.
    @param str: current rack
    @param str: desired word from rack
    @return True if desired_str in rack_str, else False
    """
    for letter in desired_str:
        if letter in rack_str:
            rack_str = rack_str.replace(letter, "", 1)
        elif "?" in rack_str:
            rack_str = rack_str.replace("?", "", 1)
        else:
            return False

        # Empty sequence evaluates to False in Python; more 'Pythonic'
        if not rack_str:
            return True


def main():
    """
    Main function that will be used to start the program.
    """
    racks = []

    with open("racks.txt", "r") as all_racks:
        for rack in all_racks.readlines():
            rack_io = rack.split(";")
            racks.append([rack_io[0], rack_io[1][:-1]])

    for rack_io in racks:
        print("scrabble({}, {})  ->  {}".format(
            rack_io[0],
            rack_io[1],
            str(scrabble(rack_io[0], rack_io[1]))
        ))


if __name__ == '__main__':
    main()

racks.txt

pizza??;pizzazz
piizza?;pizzazz
a??????;program
b??????;program
pizza??;pizzazz
piizza?;pizzazz
a??????;program
b??????;program