Craftbd/.block

## .block
license: mit

## README.md

      
    Raw
  

              README.md
            
          
    Built with blockbuilder.org
forked from scresawn's block: Sample problems: objects and arrays
forked from scresawn's block: Sample problems 2: objects and arrays

  
## index.html
<!DOCTYPE html>
<head>
  <meta charset="utf-8">
  <script src="https://d3js.org/d3.v4.min.js"></script>
  <style>
    body { margin:0;position:fixed;top:0;right:0;bottom:0;left:0; }
  </style>
</head>

<body>
  <h1>Please look in the code below for 4 JavaScript practice problems.</h1>
  <p>(These problems don't include any SVG manipulation, so you will need to open the developer console in order to see the output of your code)</p>
  <script>


  // Problem 1: search array1 for those states whose location is "East"
  // using console.log(), print just the state name(s).

array1 = [
    				{name: "Arizona",  location: "Southwest"},
           	{name: "Virginia", location: "East"},
            {name: "Florida",  location: "Southeast"}
           ];

console.log("QUESTION 1")

	array1.forEach(function(s) {
  if(s.location == 'East') {
  console.log(s)
  }
});


  // Problem 2: search array1 (above) for those states whose location contains the substring "South"
console.log("QUESTION 2")
  array1.forEach(function(s) {
  if(s.location.includes("South")) {
  console.log(s)
  }
});


  // using console.log(), print just the state name(s) for these states.


  // Problem 3: using iteration and console.log(), print those items that are in
  // array2 but NOT in array3

 var array2 = ['a','b','c', 65, 'd'];
 var array3 = ['a','c','e','f','g', 87];
console.log("QUESTION 3")

array2.forEach(function (i){
  if (array3.includes(i) == false){
    console.log(i)
  }
})

  // Problem 4: 'states' is an array of objects. Sort the array in ascending order
  // by state name


  states = [{name: "Alaska", id: "AK", population: 741894},
            {name: "Virginia", id: "VA", population: 8411808},
    				{name: "Arizona", id: "AZ", population: 6931071},
            {name: "Florida", id: "FL", population: 20984400}]

  console.log("QUESTION 4")
//states.sort(functon (a,b) {
  // return d3.ascending ( a.name, b.name)
   //         });
console.log(states)


  // Problem 5: write code that determines which state(s) have a population value that is an even number. Print out the state(s) to the console

console.log("QUESTION 5")
states.sort(function(a,b){return(a.population)<(b.population)});
console.log(states)

states.forEach(function(i){
  console.log(i.name, i.population,)
  if (i.population % 2 == 0) {
    console.log(i)
  }
})


/* Question 2 on problem #3

var average = 0;
    console.log(states.length)
    for (i=0, i< state.length; i++){
      average += state[i].population;
    }
average = average / states.length;*/


/*

var populations = 0;
var numberofstates = 0;

states.forEach(function(d){
	population += d.population;
	numberofStates++;
})

var mean = populations / numberofStates;
or**** var mean2 = populations / states.length;
console.log(" solution 3: ", mean) */


// var x;
// x = x+1
//x+ = 1;
//x++
// all the same type


  </script>
</body>
	<!DOCTYPE html>
	<head>
	<meta charset="utf-8">
	<script src="https://d3js.org/d3.v4.min.js"></script>
	<style>
	body { margin:0;position:fixed;top:0;right:0;bottom:0;left:0; }
	</style>
	</head>

	<body>
	<h1>Please look in the code below for 4 JavaScript practice problems.</h1>
	<p>(These problems don't include any SVG manipulation, so you will need to open the developer console in order to see the output of your code)</p>
	<script>


	// Problem 1: search array1 for those states whose location is "East"
	// using console.log(), print just the state name(s).

	array1 = [
	{name: "Arizona", location: "Southwest"},
	{name: "Virginia", location: "East"},
	{name: "Florida", location: "Southeast"}
	];

	console.log("QUESTION 1")

	array1.forEach(function(s) {
	if(s.location == 'East') {
	console.log(s)
	}
	});


	// Problem 2: search array1 (above) for those states whose location contains the substring "South"
	console.log("QUESTION 2")
	array1.forEach(function(s) {
	if(s.location.includes("South")) {
	console.log(s)
	}
	});


	// using console.log(), print just the state name(s) for these states.


	// Problem 3: using iteration and console.log(), print those items that are in
	// array2 but NOT in array3

	var array2 = ['a','b','c', 65, 'd'];
	var array3 = ['a','c','e','f','g', 87];
	console.log("QUESTION 3")

	array2.forEach(function (i){
	if (array3.includes(i) == false){
	console.log(i)
	}
	})

	// Problem 4: 'states' is an array of objects. Sort the array in ascending order
	// by state name


	states = [{name: "Alaska", id: "AK", population: 741894},
	{name: "Virginia", id: "VA", population: 8411808},
	{name: "Arizona", id: "AZ", population: 6931071},
	{name: "Florida", id: "FL", population: 20984400}]

	console.log("QUESTION 4")
	//states.sort(functon (a,b) {
	// return d3.ascending ( a.name, b.name)
	// });
	console.log(states)


	// Problem 5: write code that determines which state(s) have a population value that is an even number. Print out the state(s) to the console

	console.log("QUESTION 5")
	states.sort(function(a,b){return(a.population)<(b.population)});
	console.log(states)

	states.forEach(function(i){
	console.log(i.name, i.population,)
	if (i.population % 2 == 0) {
	console.log(i)
	}
	})













	/* Question 2 on problem #3

	var average = 0;
	console.log(states.length)
	for (i=0, i< state.length; i++){
	average += state[i].population;
	}
	average = average / states.length;*/


	/*

	var populations = 0;
	var numberofstates = 0;

	states.forEach(function(d){
	population += d.population;
	numberofStates++;
	})

	var mean = populations / numberofStates;
	or**** var mean2 = populations / states.length;
	console.log(" solution 3: ", mean) */


	// var x;
	// x = x+1
	//x+ = 1;
	//x++
	// all the same type

















	</script>
	</body>