Created
September 5, 2016 10:40
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#!/usr/bin/python | |
import math | |
def isqrt(n): | |
x = n | |
y = (x + 1) // 2 | |
while y < x: | |
x = y | |
y = (x + n // x) // 2 | |
return x | |
with open("key1", "r") as f: | |
n1 = int(f.readline()) | |
e1 = int(f.readline()) | |
with open("key2", "r") as f: | |
n2 = int(f.readline()) | |
e2 = int(f.readline()) | |
diffq = ((n2 - n1) - 4) / 2 | |
print " [!] solving for p..." | |
import sympy | |
import sys | |
a = -1 | |
b = diffq | |
c = 0 - n1 | |
x = sympy.Symbol('x') | |
p = int(max(sympy.solve(a*x**2 + b*x + c, x))) | |
print " [*] quadratic equation solved" | |
q = n1 / p | |
# print q | |
if p * q == n1: | |
print " [*] solved: p*q == n1" | |
else: | |
print " [-] not solved: p*q != n, remainder = %d" % (n1 % p) | |
sys.exit(0) | |
if (p+2) * (q+2) == n2: | |
print " [*] confirmed: (p+2) * (q+2) == n2" | |
else: | |
print " [-] not confirmed, twin prime does not match n2" | |
sys.exit(0) | |
print " [+] stage2: undoing shitfest RSA" | |
from Crypto.Util.number import * | |
import Crypto.PublicKey.RSA as RSA | |
import os | |
e = long(65537) | |
d1 = inverse(e, (p-1)*(q-1)) | |
d2 = inverse(e, (p+1)*(q+1)) | |
key1 = RSA.construct((n1, e, d1)) | |
key2 = RSA.construct((n2, e, d2)) | |
with open("encrypted","r") as f: | |
c = int(f.readline()) | |
c = key2.decrypt(c) | |
c = key1.decrypt(c) | |
print long_to_bytes(c) |
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