Skip to content

Instantly share code, notes, and snippets.

What would you like to do?
Variadic compose by multiple calls
var compose = function compose(f) {
var queue = f ? [f] : [];
var fn = function fn(g) {
if (arguments.length) {
return fn;
return function() {
var args =;
queue.forEach(function(func) {
args = [func.apply(this, args)];
return args[0];
return fn;
var add1 = function(x) {return x + 1;};
var mult2 = function(x) {return x * 2;};
var square = function(x) {return x * x;};
var negate = function(x) {return -x;};
var f = compose(add1)(mult2)(square)(negate)();
console.assert(-36, f(2), "f(2)");

This comment has been minimized.

Copy link

zhirzh commented Jun 8, 2016

this is currying, not composing.
composing would have [psuedo] syntax like:

function compose(f, g, h) {
  return function(x) {
    return f(g(h(x)));
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
You can’t perform that action at this time.
You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Reload to refresh your session.