A $B$ C $(D)$
renders as
A
Oddly, if you leave out A B or C, it works fine
-
$B$ C$(D)$ - A C
$(D)$ - A
$B$ $(D)$
Other examples
- A
$B$ C$D)$ - A
$B$ C$(D$ - A
$B$ C$D$
Created
June 16, 2022 19:34
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