Create a diff of code only if there is no debug code present

makediff

#!/bin/bash

#For creating a code review diff.  Making sure that no debugging code is located in the diff.
#This file will not create the diff if there are dump, print_r or NOCOMMIT statements.
#As echo and alert statements may be valid code, a warning is generated and a diff is made.

cd ~/whitelabel

branchName=$2
diffName=$1

diff=$(git diff $branchName)

if [ ${#diff} -eq 0 ]; then
        echo There is no difference
        exit
fi

dump=$(git diff $branchName | egrep 'dump|print_r|NOCOMMIT|console.log|die|{debug}')

if [ ${#dump} -gt 0 ]; then
        echo $dump \n
        echo You have debugging code in your diff
else
        warnings=$(git diff $branchName | egrep 'echo|alert')

        if [ ${#warnings} -gt 0 ]; then
                echo $warnings \n
                echo Please make sure that these are not for debugging
        else
                echo No Debugging code
        fi
 
        git diff $branchName > ~/Diff/$1
         echo ~/Diff/$1 created
fi