Bash script to prevent committing debug code in Git

commit

#!/bin/bash

for args in $@
do
	case "$args" in

"-f"|"--force")
	force=true
;;
	esac
done

debugCode=$(git diff --staged | egrep 'dump|print_r|nocommit|console.log|die|{debug}' -i)

if [ ${#debugCode} -gt 0 ]; then
	echo You have debugging code that you are trying to commit
	commit=false
else
	commit=true
fi

if [ $force -o $commit ]; then
	git commit
fi