Commit script to prevent git from committing code with debugging in it

gistfile1.sh

#!/bin/bash
 
for args in $@
do
  case "$args" in
 
"-f"|"--force")
	force=true
;;
	esac
done
 
debugCode=$(git diff --staged | egrep 'dump|print_r|nocommit|console.log|die|{debug}' -i)
 
if [ ${#debugCode} -gt 0 ]; then
	echo You have debugging code that you are trying to commit
	commit=false
else
	commit=true
fi
 
if [ $force -o $commit ]; then
	git commit
fi