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@EvelynSubarrow
Last active February 23, 2016 20:03
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Project Euler, problem 8, abusing kotlin lambdas
fun main(args :Array<String>)
{
println(solve(
"7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843" +
"8586156078911294949545950173795833195285320880551112540698747158523863050715693290963295227443043557" +
"6689664895044524452316173185640309871112172238311362229893423380308135336276614282806444486645238749" +
"3035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776" +
"6572733300105336788122023542180975125454059475224352584907711670556013604839586446706324415722155397" +
"5369781797784617406495514929086256932197846862248283972241375657056057490261407972968652414535100474" +
"8216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586" +
"1786645835912456652947654568284891288314260769004224219022671055626321111109370544217506941658960408" +
"0719840385096245544436298123098787992724428490918884580156166097919133875499200524063689912560717606" +
"0588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450"))
}
fun solve(series :String) :Long =
0.toLong().let{ var value :Long = 0; Array(series.length, {series[it].toLong() - '0'.toLong()}).let{ moo -> IntRange(0, moo.size-13).forEach { i-> value = (moo.slice(IntRange(i, i + 12)) + 1).reduceRight{ x, y -> x * y }.let{if (it > value) it else value } } }.let{ value }; value }
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