Day 8: 100 Days of SwiftUI – Hacking with Swift. Checkpoint 4

Checkpoint4.swift

import Cocoa

///Write a function that accepts an integer from 1 through 10,000, and returns the integer square root of that number.
///You can’t use Swift’s built-in sqrt() function or similar – you need to find the square root yourself.
///If the number is less than 1 or greater than 10,000 you should throw an “out of bounds” error.
///You should only consider integer square roots – don’t worry about the square root of 3 being 1.732, for example.
///If you can’t find the square root, throw a “no root” error.

enum isqrError: Error {
    case noRoot, outOfBounds
}

func returnIntegerSquareRoot(for number: Int) throws -> String {
    if number < 1 || number > 10_000 {
        throw isqrError.outOfBounds
    }
//To find a sqare root of a number without using sqrt(), find out which whole number, multiplied by itsself, returns the number.
//e.g sqrt of 25 is 5 because 5x5=25
    for i in 1...100 {
        if number == i * i {
            return "The square root of \(number) is \(i)"
        }
    }
    throw isqrError.noRoot
}

for i in 0...10_001 {
    do {
        let answer = try returnIntegerSquareRoot(for: i)
        print(answer)
    } catch {
        print(error)
    }
}