Created
February 25, 2018 19:54
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Generar números de Dudeney en C# con LINQ.
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void Main() | |
{ | |
Enumerable.Range(0, 1000) | |
.Where(e => Math.Pow(e.Digitos().Sum(), 3) == e) | |
.Dump("Números de Dudeney entre 0 y 1000"); | |
} | |
public static class ExtractorDigitos | |
{ | |
// Método de extensión para extraer los digitos de un número> | |
public static IEnumerable<int> Digitos(this int numero) | |
{ | |
List<char> caracteres = new List<char>() { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' }; | |
List<int> digitos = new List<int>(); | |
foreach (char caracter in numero.ToString()) | |
{ | |
digitos.Add(caracteres.IndexOf(caracter)); | |
} | |
return digitos.AsEnumerable(); | |
} | |
} |
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