Find array value products

products.py

def arrayProducts(arr):
	if arr == None: return []
	if len(arr) == 1: return [0]

	left_mul = 1 #this holds product so far from the left side 
	for i in range(len(arr)):
		right_mul = 1 
		for j in range(i+1, len(arr)): # this loops from the index of the current value + 1 to the end
			right_mul *= arr[j] 
		temp_v = arr[i]
		arr[i] = left_mul *right_mul
		left_mul *= temp_v
	return arr

Hello @Fredpwol, thank you for participating in Week 4 of Algorithm Fridays.

Your solution works for most test cases, however it fails for the test case for when one of the elements of the array is 0.

arrayProducts([4, 3, 0]); ❌ // should return [0, 0, 12] but yours returns [0, 0, 0]

Also, do you think we can better optimize this in terms of memory usage? Do we have to create a new res array?

Kudos all the same for a good attempt!

Hello @meekg33k, Thank you for the response,

I have taken note of all my issues and missing edge cases so here's my new solution please check it out.