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// 这个版本不支持赋值运算 | |
#include <stdlib.h> | |
#include <stdio.h> | |
#include <string.h> | |
void preproccess(char *buf, int a, int b, int c, int d, int e); | |
void replace(char *buf, int start, int end, int number); | |
void mult_analytic(char *buf); | |
void remove_bracket(char *buf); | |
void analytic(char *buf, char *op); | |
int calculate(char *buf, int n); | |
void preproccess(char *buf, int a, int b, int c, int d, int e) | |
{ | |
int i = 0; | |
while(buf[i] != 0) | |
{ | |
if(buf[i] == ' ') | |
strcpy(buf+i, buf+i+1); | |
else if(buf[i] == '>' && buf[i+1] == '>') | |
strcpy(buf+i, buf+i+1); | |
else if(buf[i] == '<' && buf[i+1] == '<') | |
strcpy(buf+i, buf+i+1); | |
else | |
i++; | |
} | |
} | |
void replace(char *buf, int start, int end, int number) | |
{ | |
char t_buf_1[20]; | |
char t_buf_2[20]; | |
int i = 0; | |
itoa(number, t_buf_1, 10); | |
strcpy(t_buf_2, buf+end+1); | |
strcpy(buf+start, t_buf_1); | |
strcat(buf+start+strlen(t_buf_1), t_buf_2); | |
} | |
void mult_analytic(char *buf) | |
{ | |
char op[6][3] = { | |
{'*', '/', '%'}, | |
{'+', '-', '-'}, | |
{'<', '>', '>'}, | |
{'&', '&', '&'}, | |
{'^', '^', '^'}, | |
{'|', '|', '|'} | |
}; | |
int i = 0; | |
remove_bracket(buf); | |
while(i < 6) | |
{ | |
analytic(buf, op[i++]); | |
} | |
} | |
void remove_bracket(char *buf) | |
{ | |
int i = 0; | |
int j = 0; | |
int k = 0; | |
char t_buf[20]; | |
while(buf[i] != 0) | |
{ | |
if(buf[i] == '(') | |
++j; | |
else if(buf[i] == ')') | |
++k; | |
i++; | |
} | |
if(j != k) // 判断括号配对 | |
return; | |
else if(j == 0) // 判断有无括号 | |
return; | |
j = k = -1; | |
i = 0; | |
while(buf[i] != 0) // 寻找最内层括号 | |
{ | |
if(buf[i] == '(') | |
j = i; | |
else if(buf[i] == ')') | |
{ | |
k = i; | |
break; | |
} | |
i++; | |
} | |
if(k != -1 && j == -1) | |
return; | |
// 分析括号里面的式子,存入t_buf | |
strcpy(t_buf, buf + j + 1); | |
t_buf[k-j-1] = '\0'; | |
mult_analytic(t_buf); // 分析并计算式子 | |
replace(buf, j, k, atoi(t_buf)); | |
remove_bracket(buf); | |
} | |
void analytic(char *buf, char* op) | |
{ | |
int i = 0; | |
int j = 0; | |
int k = 0; | |
if(buf[i] == '-' && isdigit(buf[i+1])) | |
i++; | |
while(buf[i] != 0) | |
{ | |
if(buf[i] == op[0] || buf[i] == op[1] || buf[i] == op[2]) | |
{ | |
break; | |
} | |
i++; | |
} | |
if(i >= strlen(buf)) | |
return; | |
j = k = i; | |
while(isdigit(buf[j-1])) | |
--j; | |
if(j == 1 && buf[0] == '-' && isdigit(buf[1])) | |
--j; | |
if(buf[k+1] == '-' && isdigit(buf[k+2])) | |
++k; | |
while(isdigit(buf[k+1])) | |
++k; | |
replace(buf, j, k, calculate(buf + j, k-j+1)); | |
analytic(buf, op); | |
} | |
int calculate(char *buf, int n) | |
{ | |
char t_buf_1[20]; | |
char t_buf_2[20]; | |
char op; | |
int a = 0; | |
int b = 0; | |
int i = 0; | |
if(buf[i] == '-' && isdigit(buf[i+1])) | |
i++; | |
while(isdigit(buf[i])) | |
i++; | |
if(i >= strlen(buf)) | |
return atoi(buf); | |
strncpy(t_buf_1, buf, i); | |
t_buf_1[i] = 0; | |
op = buf[i]; | |
strncpy(t_buf_2, buf + i + 1, n-i-1); | |
t_buf_2[n-i-1] = '\0'; | |
a = atoi(t_buf_1); | |
b = atoi(t_buf_2); | |
switch(op) | |
{ | |
case '*': return (a*b); | |
case '/': return (a/b); | |
case '%': return (a%b); | |
case '+': return (a+b); | |
case '-': return (a-b); | |
case '<': return (a<<b); | |
case '>': return (a>>b); | |
case '^': return (a^b); | |
case '&': return (a&b); | |
case '|': return (a|b); | |
default: return 0; | |
} | |
return 0; | |
} | |
int main(void) | |
{ | |
int a, b, c, d, e; | |
char buf[60]; | |
puts("input a b c d e"); | |
scanf("%d %d %d %d %d", &a, &b, &c, &d, &e); | |
fflush(stdin); | |
puts("input a expression"); | |
gets(buf); | |
preproccess(buf, a, b, c, d, e); | |
mult_analytic(buf); | |
printf("= %d\n", atoi(buf)); | |
system("pause"); | |
return 0; | |
} |
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