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One possible solution for the famous "Fizz Buzz" problem
/*
* Project Name: FizzBuzz
* Solution Name: FizzBuzz
* Original creation date: 18/04/2011
* Edit date: 18/01/2013
* Programmer name: Jamie Taylor (aka "GaProgMan")
* File name: FizzBuzz.cpp
*
* Purpose of the project:
* This code is my solution for a common programmer
* test called "FizzBuzz".
* It is used by many who recruit programmers to see
* if the prospective programmer is worth hiring.
* More information on this problem can be found at a
* Coding Horror article called "Why Programmers can't
* Program" by Jeff Attwood, here: http://bit.ly/cakJHF
* The original problem can be found in the following
*comment block.
*
* Problem Discussion:
* Write a program that prints the numbers from 1 to
* 100. But for multiples of three print "Fizz" instead
* of the number and for the multiples of five print
* "Buzz". For numbers which are multiples of both
* three and five print "FizzBuzz".
*
* GNU Copyright information
* Copyright 2011 Jamie Taylor <jamie@taylorj.org.uk>
*
* This program is free software; you can redistribute
* it and/or modify it under the terms of the GNU General
* Public License as published by the Free Software
* Foundation; either version 2 of the License, or (at
* your option) any later version.
*
* This program is distributed in the hope that it will
* be useful, but WITHOUT ANY WARRANTY; without even the
* implied warranty of MERCHANTABILITY or FITNESS FOR A
* PARTICULAR PURPOSE. See the GNU General Public
* License for more details.
*
* You should have received a copy of the GNU General
* Public License along with this program; if not, write
* to the Free Software Foundation, Inc., 51 Franklin
* Street, Fifth Floor, Boston, MA 02110-1301, USA.
*/
#include <stdio.h>
using namespace std;
int main () {
for ( int i = 1; i <= 100; i++ ) {
if ( ( i % 3 == 0 ) && ( i % 5 == 0 ) )
cout << "FizzBuzz" << endl;
else if (i % 5 == 0)
cout << "Buzz" endl;
else if (i % 3 == 0)
cout << "Fizz" << endl;
else
cout << i << endl;
}
return 0;
}
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