One possible solution for the famous "Fizz Buzz" problem

FizzBuzz.cpp

/*
 * Project Name:            FizzBuzz
 * Solution Name:           FizzBuzz
 * Original creation date:  18/04/2011
 * Edit date:               18/01/2013
 * Programmer name:         Jamie Taylor (aka "GaProgMan")
 * File name:               FizzBuzz.cpp
 *
 * Purpose of the project:
 *  This code is my solution for a common programmer
 * test called "FizzBuzz".
 *  It is used by many who recruit programmers to see
 * if the prospective programmer is worth hiring.
 * More information on this problem can be found at a
 * Coding Horror article called "Why Programmers can't
 * Program" by Jeff Attwood, here: http://bit.ly/cakJHF
 *  The original problem can be found in the following
 *comment block.
 *
 * Problem Discussion:
 *   Write a program that prints the numbers from 1 to
 * 100. But for multiples of three print "Fizz" instead
 * of the number and for the multiples of five print
 * "Buzz". For numbers which are multiples of both
 * three and five print "FizzBuzz".
 *
 *    GNU Copyright information
 *    Copyright 2011 Jamie Taylor <jamie@taylorj.org.uk>
 *
 *    This program is free software; you can redistribute
 *        it and/or modify it under the terms of the GNU General
 *        Public License as published by the Free Software
 *        Foundation; either version 2 of the License, or (at
 *	your option) any later version.
 *
 *	This program is distributed in the hope that it will
 *	be useful, but WITHOUT ANY WARRANTY; without even the
 *	implied warranty of MERCHANTABILITY or FITNESS FOR A
 *	PARTICULAR PURPOSE.  See the GNU General Public
 *	License for more details.
 *
 *	You should have received a copy of the GNU General
 *	Public License along with this program; if not, write
 *	to the Free Software Foundation, Inc., 51 Franklin
 *	Street, Fifth Floor, Boston, MA 02110-1301, USA.
*/

#include <stdio.h>
using namespace std;
int main () {
  for ( int i = 1; i <= 100; i++ ) {
    if ( ( i  % 3 == 0 ) && ( i % 5 == 0 ) )
      cout << "FizzBuzz" << endl;
    else if (i % 5 == 0)
	  cout << "Buzz" endl;
	else if (i % 3 == 0)
	  cout << "Fizz" << endl;
	else
	  cout << i << endl;
  }
  return 0;
}