Created
February 22, 2022 01:10
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template <typename T> | |
auto popcount8R (const T & val) -> int | |
{ | |
static_assert (std::is_integral <T> :: value && ! std::is_signed <T> :: value); | |
if (val == 0) | |
return 0; | |
const unsigned char m1 = 0b01010101; | |
const unsigned char m2 = 0b00110011; | |
const unsigned char m4 = 0b00001111; | |
const unsigned char r = val & 0b11111111; | |
const unsigned char a = (r & m1) + ((r >> 1) & m1); | |
const unsigned char b = (a & m2) + ((a >> 2) & m2); | |
const unsigned char c = (b & m4) + ((b >> 4) & m4); | |
return c + popcount8R ((T) (val >> 8)); | |
} | |
auto popcount64 (const uint64_t & val) -> int | |
{ | |
const uint64_t m1 = 0b0101010101010101010101010101010101010101010101010101010101010101; | |
const uint64_t m2 = 0b0011001100110011001100110011001100110011001100110011001100110011; | |
const uint64_t m4 = 0b0000111100001111000011110000111100001111000011110000111100001111; | |
const uint64_t a = val - ((val >> 1) & m1); // bit a, bit b, (a << 1) + b - a = 2a + b - a = a + b | |
const uint64_t b = (a & m2) + ((a >> 2) & m2); // again apply the mask first, because | |
// the sum of two 2 bit integers can take more than 2 bits | |
// (max: 3) | |
uint64_t c = (b + (b >> 4)) & m4; // take the advantage, that the sum of two 3 bit integers can't take | |
// more than 4 bits (max: 4) | |
# ifndef __FAST_MUL_OR_SOMETHING_LIKE_THIS | |
c += c >> 8; // take the advantage, that the sum of two 4 bit integers can't take more than 8 bits (max 5) | |
c += c >> 16; // take the advantage, that the sum of two 5 bit integers can't take more than 8 bits (max 6) | |
c += c >> 32; // take the advantage, that the sum of two 6 bit integers can't take more than 8 bits (max 7) | |
c &= (1ull << 7) - 1; // take the rightmost 7 bits (the sum of all 64 bits) | |
# else | |
const uint64_t h01 = 0b0000000100000001000000010000000100000001000000010000000100000001; | |
c = (c * h01) >> (7 * 8); // combine the sum in the leftmost 8 bits and fix the position: | |
/* | |
c * h01 = c * (1 + (1 << 8) + (1 << 16) + (1 << 24) + (1 << 32) + (1 << 40) + (1 << 48) + (1 << 56)) = | |
= c + (c << 8) + (c << 16) + (c << 32) + (c << 40) + (c << 48) + (c << 56) | |
*/ | |
// NOTE: overflow happens there, I'm not sure how the multiplication is implemented, | |
// so this can give a wrong value. | |
# endif | |
return c; | |
} |
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