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@GeHou
Created January 20, 2015 08:18
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给定日期之间的周末天数
/*
| @param char|int $start_date 一个有效的日期格式,例如:20091016,2009-10-16
| @param char|int $end_date 同上
| @return 给定日期之间的周末天数
*/
function get_weekend_days($start_date,$end_date){
if (strtotime($start_date) > strtotime($end_date)) list($start_date, $end_date) = array($end_date, $start_date);
$start_reduce = $end_add = 0;
$start_N = date('N',strtotime($start_date));
$start_reduce = ($start_N == 7) ? 1 : 0;
$end_N = date('N',strtotime($end_date));
in_array($end_N,array(6,7)) && $end_add = ($end_N == 7) ? 2 : 1;
$days = abs(strtotime($end_date) - strtotime($start_date))/86400 + 1;
return floor(($days + $start_N - 1 - $end_N) / 7) * 2 - $start_reduce + $end_add;
}
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