make std::function from lambda without describing explicit function type

make_function.cpp

#include<functional>
namespace make_function{
   template<class R = void,class C = void,class... A>
   struct impl;
    
   template<class R,class C,class... A>
   struct impl<R (C::*)(A...)const>{
        using type = R(*)(A...);
   };
    
    template<class T>
    auto make_f(T arg){
        using type = decltype(&T::operator());
        return typename impl<type>::type{arg};
    }
}

int main(){
    auto tmp = make_function::make_f([](int,char)->int{return 0;});
    tmp(1,'a');
    
}