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from binascii import unhexlify | |
import math | |
# STEP 1 => Get the bytes of the flag | |
encrypted_flag = unhexlify(open('output.txt','r').read().split(' ')[1].strip('\n')) | |
part_flag = b'HTB{' | |
# STEP 2 => Get the encryption key by xoring the known string with the similar placed output bytes | |
key = [chr(b ^ encrypted_flag[a]) for a,b in enumerate(part_flag)] | |
messages = [] | |
#STEP 3 => decrypt the flag now that we have the key | |
for i in range(int(len(encrypted_flag) / len(key)) + 1): | |
k = math.floor(len(encrypted_flag)/len(key)) * key if len(encrypted_flag) % len(key) == 0 else math.floor(len(encrypted_flag)/len(key)) * key + key[:len(encrypted_flag)%len(key)] | |
message = b'' | |
size = len(key) | |
d = encrypted_flag[size*i:size*(i+1)] | |
for a,b in enumerate(d): | |
message += bytes(chr(b ^ ord(key[a])),'utf-8') | |
messages.append(message) | |
print(b''.join(messages)) | |
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