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@Grubba27
Created April 19, 2022 01:00
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Division made in TS types
// Multiplication comes from this issue: https://github.com/type-challenges/type-challenges/issues/5814
type Reverse<A> =
`${A}` extends `${infer AH}${infer AT}`
? `${Reverse<AT>}${AH}` : A
type Digs = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
type DigsNext<I = Digs, R = {}> =
I extends [infer Head, infer Next, ...infer Tail]
? DigsNext<[Next, ...Tail], R & Record<Head, Next>>
: { [K in keyof R]: R[K] }
type DigsPrev = { [K in keyof DigsNext as DigsNext[K]]: K }
type AddOne<A> =
A extends `${infer AH}${infer AT}`
? AH extends '9' ? `0${AddOne<AT>}` : `${DigsNext[AH]}${AT}`
: `1`
type SubOne<A> =
A extends `${infer AH}${infer AT}`
? AH extends '0' ? `9${SubOne<AT>}` : `${DigsPrev[AH]}${AT}`
: never
type Add<A, B> =
A extends `${infer AH}${infer AT}` ?
B extends `${infer BH}${infer BT}`
? BH extends '0' ? `${AH}${Add<AT, BT>}` : Add<AddOne<A>, SubOne<B>>
: A : B
type Mul<A, B, R = '0'> =
A extends '0' ? R :
B extends '0' ? R :
A extends `${infer AH}${infer AT}`
? AH extends '0' ? Mul<AT, `0${B}`, R> : Mul<SubOne<A>, B, Add<R, B>>
: R
type Multiply<A extends string | number | bigint, B extends string | number | bigint> =
Reverse<Mul<Reverse<A>, Reverse<B>>>
type GreaterThan<
T extends number,
U extends number,
C extends unknown[] = []
> =
T extends U
? false
: C['length'] extends T
? false
: C['length'] extends U
? true
: GreaterThan<T, U, [...C, 1]>;
type ToNumber<
S extends string,
L extends number[] = []
> =
`${L['length']}` extends S
? L['length']
: ToNumber<S, [...L, 0]>;
type Sub<
A extends string,
B extends string,
R extends string = "0"
> =
B extends R
? A
: Sub<SubOne<A>, B, AddOne<R>>;
const sub: Sub<"5", "2"> = "3"
const sub: Sub<"9", "8"> = "1"
const sub: Sub<"8", "4"> = "4"
type Division<
W extends string,
D extends string,
Q extends string = '0'
> =
W extends '0'
? Q
: Division<Sub<W, D>, D, AddOne<Q>>
const div: Division<"2", "2"> = "1"
const div: Division<"4", "2"> = "2"
const div: Division<"8", "2"> = "4"
const div: Division<"9", "3"> = "3"
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