sort and groupby record.py

from operator import itemgetter

rows = [{'address': '5412 N CLARK', 'date': '07/01/2012'},
        {'address': '5148 N CLARK', 'date': '07/04/2012'},
        {'address': '5800 E 58TH', 'date': '07/02/2012'},
        {'address': '2122 N CLARK', 'date': '07/03/2012'},
        {'address': '5645 N RAVENSWOOD', 'date': '07/02/2012'},
        {'address': '1060 W ADDISON', 'date': '07/02/2012'},
        {'address': '4801 N BROADWAY', 'date': '07/01/2012'},
        {'address': '1039 W GRANVILLE', 'date': '07/04/2012'}, ]

rows.sort(key=itemgetter("date"))
print(rows)

# now group by
from itertools import groupby


rows.sort(key=itemgetter("date"))

for date, item in groupby(rows, key=itemgetter('date')):
    print(date)
    for i in item:
        print('   ', i)