unique sort using scala

uniqueSort.scala

//unique sort using scala
object Main extends App {
    val array=Array(5,4,7,6,5,5,4,3,3,3,2,5,5,1,2)
    util.Sorting.quickSort(array)
    val newArray = array.foldRight(List.empty[Int]){ 
      case (a, b) => 
        if (!b.isEmpty && b(0) == a) 
          b 
        else 
          a :: b 
    }
    for(s <- newArray) println(s)
}