961. N-Repeated Element in Size 2N Array - https://leetcode.com/problems/n-repeated-element-in-size-2n-array/

NRepeatedElements.py

class Solution:
    def repeatedNTimes(self, A: List[int]) -> int:
        for i in range(len(A)):
            if A.count(A[i]) == len(A)//2:
                return A[i]
            
            
            
            
"""
Input: [1,2,3,3]
Output: 3

size 2N
N+1 unique
N=2
T = 3

Input: [2,1,2,5,3,2]
Output: 2

size 2N
N+1 unique
N=3
T=2

Input: [5,1,5,2,5,3,5,4]
Output: 5
N 5

"""